Answer : The temperature of boiling water of part A (in Kelvin) = 373.15 K
The temperature of boiling water of part B (in Kelvin) = 372.15 K
The final temperature of cooling water of part A (in Kelvin) = 296.15 K
The final temperature of cooling water of part B (in Kelvin) = 280.15 K
Solution : Given,
The temperature of boiling water of part A =
The temperature of boiling water of part B =
The final temperature of cooling water of part A =
The final temperature of cooling water of part B =
Conversion of into Kelvin.
By using this conversion, we get
The temperature of boiling water of part A = = 100 + 273.15 = 373.15 K
The temperature of boiling water of part B = = 99 + 273.15 = 372.15 K
The final temperature of cooling water of part A = = 23 + 273.15 = 296.15 K
The final temperature of cooling water of part B = = 7 + 273.14 = 280.15 K