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2 years ago

Please Help!!!!!!!!!!!!!!

Chemistry

2 answers:

defon2 years ago

8 0

Answer:

i can't see it

Explanation:

gladu [14]2 years ago

5 0

So wouldn’t you just type the scientific notation that it gave you into a calculator and then get the answer?

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What is the mass percent of water in copper (II) sulfate?

Veseljchak [2.6K]

The answer is sulfate pentahydrate

Hope this helps you :D

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3 years ago

Select the correct answer.

givi [52]

Answer:

{1s^2 2s^2 2p^6} 3s^2 3p^4

{Ne}3s^2 3p^4

Explanation:

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6 0

2 years ago

How many atoms are there in 5.70 mol of hanfnium?

ANTONII [103]

The correct answer would be 3.49 times 10^ minus 24 molecules

6 0

3 years ago

A serving of Frosted Flakes cereal contains 235,000 J of energy. Calculate the change in temperature (ΔT) that would occur if th

timama [110]

The change in temperature (ΔT) : 56.14 ° C

<h3>Further explanation</h3>

Given

Cereal energy = 235,000 J

mass of water = 1000 g

Required

the change in temperature (ΔT)

Solution

Heat can be formulated :

Q = m . c . ΔT

c = specific heat for water = 4.186 J / gram ° C

235000 = 1000 . 4.186 . ΔT

$\tt \Delta T=\dfrac{235000}{1000\times 4.186}=56.14^oC$

3 0

2 years ago

In the laboratory you are asked to make a 0.175 m barium iodide solution using 13.9 grams of barium iodide. How much water shoul

BARSIC [14]

<u>Answer:</u> The mass of water that should be added in 203.07 grams

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

m = molality of barium iodide solution = 0.175 m

$m_{solute}$ = Given mass of solute (barium iodide) = 13.9 g

$M_{solute}$ = Molar mass of solute (barium iodide) = 391.14 g/mol

$W_{solvent}$ = Mass of solvent (water) = ? g

Putting values in above equation, we get:

$0.175=\frac{13.9\times 1000}{391.14\times W_{solvent}}\\\\W_{solvent}=\frac{13.9\times 1000}{391.14\times 0.175}=203.07g$

Hence, the mass of water that should be added in 203.07 grams

4 0

2 years ago