What are three physical factors that can be done to speed up a chemical reaction

One way in which elements differ from each other is the structure of the electron cloud in each elements Atoms in electron cloud

BartSMP [9]

Not sure what you are asking. I have two possible answers though...

It could either be more negatively charged, or valence electrons.

The more away from the nucleus a electron is, the more negatively charged it is.

The electrons on the outermost electron shell is valence electrons.

Again, I don't know what you were asking, but one of these answers may be correct.

4 0

3 years ago

Read 2 more answers

An ideal gas differs from a real gas in that the molecules of an ideal gas __________. a have a molecular weight of zero b have

Rasek [7]

An ideal gas differs from a real gas in that the molecules of an ideal gas have no attraction for one another.
An ideal gas is defined as one in which collisions between atoms or molecules are perfectly elastic and in which there are no inter-molecular attractive forces. A real gas on the other hand is a gas that does not behave as an ideal gas due to interactions between gas molecules. Particles in a real gas have a real volume since real gases are made up of molecules or atoms that typically take up some space even though they are extremely small.

4 0

3 years ago

At the start of a reaction, there are 0.0249 mol N2,

gladu [14]

Answer:

Explanation:

The reaction is given as:

$N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}$

The reaction quotient is:

$Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}$

From the given information:

TO find each entity in the reaction quotient, we have:

$[NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}$

$[N_2] = \dfrac{0.024 }{3.5}$

$[N_2] = 0.006857$

$[H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}$

$[H_2] = 9.17 \times 10^{-3}$

∴

$Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135$

However; given that:

$K_c = 1.2$

By relating $Q_c \ \ and \ \ K_c$ , we will realize that $Q_c \ \ < \ \ K_c$

The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.

7 0

3 years ago

To determine the limiting reactant in a chemical reaction, one must know the:.

sveticcg [70]

Answer:

The available amounts of each reactant

Explanation:

The limiting reactant is the reactant that will limit the equation.

For example, I have 2N2 and H2O. In this situation, H2O would be the limiting reactant since there is only one atom, while N2 has two atoms.

Think of it like you're making peanut butter and jelly. You have 50 cans of peanut butter and only 10 jelly. Which means you can only make sandwiches using 10 jars of jelly and 10 jars of peanut butter.

4 0

2 years ago

For a reaction Y → X with a very high equilibrium constant, K, which of the following is true? You can refer to the following tw

Dafna11 [192]

Answer:The amount of product will be higher than the amount of substrate at equilibrium

Explanation:

Recall that the equilibrium constant K depends on the amounts of reactants and products present in the system at equilibrium.

Considering the equation; K = [X]/[Y], as the concentration of X increases above that of Y, the equilibrium constant K becomes very high, hence the answer above.

8 0

3 years ago