Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Explanation:
First we have to calculate the moles of diethyl ether
![\text{Moles of diethyl ether}=\frac{\text{Mass of diethyl ether}}{\text{Molar mass of diethyl ether}}=\frac{75.0g}{74g/mole}=1.01moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20diethyl%20ether%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20diethyl%20ether%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20diethyl%20ether%7D%7D%3D%5Cfrac%7B75.0g%7D%7B74g%2Fmole%7D%3D1.01moles)
As, 1 mole of diethyl ether require heat = 26.5 kJ
So, 1.01 moles of diethyl ether require heat = ![\frac{26.5}{1}\times 1.01=26.8kJ](https://tex.z-dn.net/?f=%5Cfrac%7B26.5%7D%7B1%7D%5Ctimes%201.01%3D26.8kJ)
Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
The answer is B.mass because like the periodic table it determines the elements by mass
Answer: hypodermis
Explanation:
The very bottom layer of the skin is the hypodermis. It contains the fat cells, or adipose tissue, that insulate the body and help it conserve heat.
God bless you!!
I can't answer this question without knowing what the specific heat capacity of the calorimeter is. Luckily, I found a similar problem from another website which is shown in the attached picture.
Q = nCpΔT
Q = (1.14 g)(1 mol/114 g)(6.97 kJ/kmol·°C)(10°C)(1000 mol/1 kmol)
<em>Q = +6970 kJ</em>
Magnesium burns with oxygen to give magnesium oxide based on the following reaction:
2M<span>g</span>+<span>O<span>2 </span></span>........> 2Mg<span>O<span>(s)</span></span>+<span>energy
</span>From the periodic table:
molecular mass of magnesium = 24.3 grams
molecular mass of oxygen = 16 grams
From the reaction:
2 x 24.3 = 48.6 grams of magnesium are required to produce 2(24.3+16) = 80.6 grams of magnesium oxide.
We can know the amount of magnesium oxide produced from 8 grams of magnesium by simply doing cross multiplication as follows:
amount of magnesium oxide = (8 x 80.6) / 48.6 = 13.267 grams