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Ratling [72]
3 years ago
10

A 2.0 kilogram ball rolling along a flat surface starts up a hill. If the ball reaches a height of 0.63 meters, what was its ini

tial speed
Physics
1 answer:
Agata [3.3K]3 years ago
5 0
The potential energy as it reaches a height of 0.63 meters is mgh
Since total mechanical energy is conserved, Set that equal to the initial kinetic energy which is 0.5mv^2

2*9.8*0.63 = 0.5*2*v^2
12.348 = v^2
3.51 = v

That's it's initial speed.
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. Find the buoyant force exerted on a ball with radius of 2 meters, when the ball is entirely immersed in the water.
almond37 [142]

Explanation:

Buoyancy force is equal to the weight of the displaced fluid:

B = ρVg

where ρ is the density of the fluid,

V is the volume of the displaced fluid,

and g is the acceleration due to gravity.

The fluid is water, so ρ = 1000 kg/m³.

The volume displaced is that of a sphere with radius 2 m:

V = 4/3 π r³

V = 4/3 π (2 m)³

V ≈ 33.5 m³

The buoyancy force is therefore:

B = (1000 kg/m³) (33.5 m³) (9.8 m/s²)

B ≈ 328,400 N

Round as needed.

8 0
3 years ago
Suppose that an Egyptian farmer claims to have discovered a linen burial cloth used during Egypt's Middle Kingdom some 4000 year
enyata [817]

Answer:

the cloth is old by 1,844 years

Explanation:

The computation is shown below:

The half-life of C^(14) is 5730 years

Now

\lambda =1.210 × 10^-4 years^(-1)

Now

N(t) = Ce^{-\lambda\times t}

0.8 \times (N_0) = N_0 \times e^{-\lambda \times t}\\\\ln(0.8) = (-\lambda \times t)\\\\t = \frac{-(ln(0.8))}{\lambda}

\lambda = .000121,

so t = 1844 yrs

hence, the cloth is old by 1,844 years

7 0
3 years ago
Energy is defined as
stira [4]

the strength and vitality required for sustained physical or mental activity.

5 0
4 years ago
Read 2 more answers
An object is placed along the principal axis of a thin converging lens that has a focal length of 16 cm. If the distance from th
Ratling [72]

Answer:

han dare push minute

Explanation:

Kean ummu

6 0
3 years ago
A 3 kilogram cat is resting on top of a bookshelf that is 3 meters high. What is the cat’s gravitational potential energy relati
Dafna1 [17]
We have: Gravitational Potential Energy (U) = mgh
Here, m = 3 Kg
g = 9.8 m/s²        [ constant value for earth system ]
h = 3 m

Substitute their values into the expression:
U = 3 × 9.8 × 3
U = 88.2 J

In short, Your Answer would be 88.2 Joules.

Hope this helps!
4 0
4 years ago
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