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rjkz [21]
3 years ago
7

Please help, i only need help with 2,5, and 7

Physics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

2. Galaxy

5. Electromagnetic radiation

7. Particle Accelerator

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PLZ HELP ME ASAP 30 POINTS
dlinn [17]

Answer:

The answer is E.

4 0
3 years ago
a body has weight 20N how much force is required to move it vertically upwards with an acceleration of 2m/s​
kramer

<h2>Given :-</h2>

  • Weight = 20 N

  • Acceleration = 2 m/s

<h2>To Find :-</h2>

  • Force applied=?

<h2>Solution :-</h2>

As we know that,

<h3>F = ma</h3>

  • F is the Force applied
  • M is the Mass
  • A is the Acceleration

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

F = 20 × 2

F = 40 N

<h3>Hence :-</h3>

Force applied is 40 N

<h2>Know More :-</h2>

  • First equation of motion
  • v = u + at

  • Second equation of motion
  • s = ut + ½at²

  • Third Equation of motion
  • v² - u² = 2as

\begin{gathered} \\ \end{gathered}

3 0
3 years ago
Please help on Problem 2.5 <br><br> I also need a short (or detailed) explanation. Thank you !!
NNADVOKAT [17]

Explanation:

Problem 2.5, mixing dough.

Please note dimensional units and standard formulas for energies.

Input:

Electrical energy = VIT = 110 V * 1.5 A * 5 min. * 60 s/min = 49500 joules = 49.5 kJ

Output:

Warming of dough = mCΔT = 1 kg  * 4.2 kJ/(kg*K) * 5 deg.K = 21 kJ

Dissipation of energy = remainder of input energy = (49.5-21) kJ = 28.5 kJ

Fraction of energy converted to energy of dough = 21 kJ / 49.5 kJ

= forty-two percent (to the nearest percent)

The last item, dissipation of energy could be attributed to:

1. Loss in efficiency of mixer in the form of mechanical friction, heating up due to resistance of motor circuit, etc.

2. Loss in mechanical mixing of dough due to friction between mixer paddle and dough in the form of heat, part of which stays with dough (thus heating up of dough), and the remainder heats up the dough container, loss of heat to environment, air, heat of vaporization of water content of dough, etc.

8 0
3 years ago
A scooter is moving with a speed of 18 m/s. Its mass is 20 kg. What is the
kykrilka [37]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

A scooter is moving with a speed of 18 m/s. Its mass is 20 kg. What is the magnitude of its momentum?

A. 360 kg.m/s

B. 2 kg.m/s

C. 3600 kg.m/s

D. 1.1 kg.m/s

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

Speed (v) of a scooter = 18 m/s

Mass (m) = 20 kg

<h3>To Find:-</h3>

Magnitude of its momentum (p) = ?

<h3>Answer:-</h3>

Since, we know that,

p = mv

So,

p = 20 kg × 18 m/s

p = 360 kg.m/s

<h3>\therefore The correct option is (A) 360 kg.m/s </h3>

<h3>The magnitude of its momentum is <u>3</u><u>6</u><u>0</u><u> </u><u>k</u><u>g</u><u>.</u><u>m</u><u>/</u><u>s</u>. [Answer]</h3>
4 0
3 years ago
How does making models help scientists observe?
Inessa [10]
By creating models scientists can have a little knowledge how specific element might look, and by the way will help them to be more creative, imaginative and reasonable.
8 0
3 years ago
Read 2 more answers
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