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Flauer [41]
3 years ago
8

Need help ??? Please

Physics
1 answer:
Yanka [14]3 years ago
8 0
Is there information in the previous question which relates to this one?
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Calculate the wavelength associated with electrons moving with p.d of 1500v
Artist 52 [7]

Answer:

3.16X10∧-11 m

Explanation:

1/2 mv2 = qV (KE = Electric potential energy)

velocity = √2qV/m = √( 2X 1.6X10∧-19 X 1500/9.11X10∧-31)

2.3X10∧7m/s

now use De Broglie equation

λ = h/mv

= 6.62X10∧-34/( 9.11X10∧-31 X 2.3X10∧7)

3.16 X 10∧-11 m

or

use the above equations and substitute to get the final eqiation

λ = h/√(2mqV) = 3.16X 10∧-11 m

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Important result of french revolution
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The french revolution led to many deaths and impacted history because of the amount of life lost
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A bar magnet moves through a loop of wire with constant velocity, and the north pole enters the loop first the induced current w
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I need help with this!! I dont have to textbook that goes with it and i cant figure anything out :(
sasho [114]

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3 0
3 years ago
A person shuffles across the rug and then place his finger near his friend's nose, causing a small spark that transfers about 10
sineoko [7]

Answer:

n = \frac{10^{-9}C}{1.6 x10^{-19}C}= 6.25 x10^{9} electrons \approx 6.3 x10^{9} electrons

Explanation:

For this case we know that the charge associated to the transferred electrons of the small spark is 10^{-19}C and we want to find the number of electrons transferred.

From the properties of matter we know that the charge of the electron is

q_e = |-1.6 x10^{-19}C |= 1.6 x10^{-19}C

And we know that the total charge is given by this expression:

Q = n e

Where Q represent the charge, n the number of electrons and e the charge of the electron.

If we solve for n we got:

n = \frac{Q}{e}

And replacing we got:

n = \frac{10^{-9}C}{1.6 x10^{-19}C}= 6.25 x10^{9} electrons \approx 6.3 x10^{9} electrons

6 0
3 years ago
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