3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.
Explanation:
data given:
H30+= 1.40 X 10^-4 M\
Henderson Hasslebalch equation to calculate pH=
pH = -log10(H30+)
putting the values in the equation:
pH = -log 10(1.40 X 10^-4 M)
pH = 3.85
pH + pOH =14
pOH = 14 - 3.85
pOH = 10.15
The OH- concentration from the pOH by the equation:
pOH = -log10[OH-]
10.5= -log10[OH-]
[OH-] = 10^-10.5
[OH-] = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.
Connective tissue is one of the four different types of tissues. It consists of cells suspended in a matrix, and consist of fibres running through it. It’s main job is to connect internal tissues. They also support and protect internal organs. Examples include cartilage, blood, lymph and adipose tissue.
Answer:
Bro the paw patrol movie is amazing
Explanation:
Answer:
True
Explanation:
Limiting reactant - the reactant which get completely consumed in a chemical reaction , is known as the limiting reactant .
As, the concentration of limiting reactant after the completion of the reaction will be zero , hence, it is used to determine the concentration of other reactants .
For example,
for a general reaction -
A + B ---> 3C
Assuming B to be the limiting reactant ,
hence, the concentration of C and A can be determined as -
1 mol of B can give 3 mol of C and 1 mol of A is used for the reaction.
Answer:
44.8L of hydrogen gas
Explanation:
The reaction expression is given as:
2Na + 2H₂O → 2NaOH + H₂
Given parameters:
Mass of sodium = 92.4g
Unknown:
Volume of hydrogen gas = ?
Solution:
To solve this problem:
1 mole of a substance at STP occupies a volume of 22.4L
Let us find the number of moles of the hydrogen gas;
Number of moles of Na = 
Molar mass of Na = 23g/mol
Number of moles = 
= 4.02mole
From the balanced reaction expression:
2 mole of Na will produce 1 mole of hydrogen gas
4.02 mole of Na will produce 
= 2mole of hydrogen gas
So
1 mole of a substance at STP occupies a volume of 22.4L
2 mole of hydrogen gas will occupy a volume of 2 x 22.4 = 44.8L of hydrogen gas
