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nataly862011 [7]
4 years ago
7

Consider an Al-4% Si alloy. Determine (a) if the alloy is hypoeutectic or hypereutectic, (b) the composition of the first solid

to form during solidification, (c) the amounts and compositions of each phase at 578˚C, (d) the amounts and compositions of each phase at 576˚C, (e) the amounts and compositions of each microconstituent at 576˚C, and (f) the amounts and compositions of each phase at 25˚C.
Chemistry
1 answer:
ozzi4 years ago
8 0

Answer:

(a) Hypoeutectic

(b) Alpha solid, aluminium

(c) 70% α , 30% β

(d) 97.6% α, 2.4% β

(e) 97.6% α, 2.4% β

(f) 97% α, 3% β

Explanation:

(a) The eutectic composition for Al Si alloy is 11.7 wt% silicon, therefore, an Al-4% Si alloy is hypoeutectic

(b) For the hypoeutectic alloy, aluminium, Al, is expected to form first, such that the aluminium content is reduced till the point it gets to the eutectic proportion of 11.7 wt% silicon

(c) At  578°C we have

% α:  Al      (11 - 4)/(11 - 1) = 70% α

% L:  Si      100 - 70 = 30% β

(d) At  576°C we have

α: 99.83% Si    (99.83 - 4)/(99.83- 1.65) = 97.6% α

β: 1.65% Si (4 - 1.65)/(99.83- 1.65) = 2.4% β

(e) Primary α: 1.65% α (99.83 - 4)/(99.83 - 1.65) = 97.6% α

Eutectic 4% Si  = 100 - 97.6 = 2.4% β

(f) At 25°C we have;

α%: (99.83 - 4)/(99.83 - 1) = 97% α

β%:   100 - 97 = 3% β.

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Explanation:

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3 years ago
0.500 mile of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (
SCORPION-xisa [38]

The correct question is as follows: 0.500 moles of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (plz help!)

Answer: The molarity of this solution is 0.25 M.

Explanation:

Molarity is the number of moles of a substance divided by volume in liter.

As it is given that there are 0.5 moles of potassium oxide in 2.00 L of water so, the molarity of this solution is calculated as follows.

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3 years ago
What is the mass of 1.71 ✕ 1023 molecules of h2so4?
Anuta_ua [19.1K]
The equation for calculating a mass is as follows:

m=n×M

Molar mass (M) we can determine from Ar that can read in a periodical table, and a number of moles we can calculate from the available date for N:

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Now we can calculate a mass of H2SO4:

m(H2SO4) = n×M = 0.3 × 98 = 27.8 g



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