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slega [8]
3 years ago
15

What is meant by Redox reaction ? ​

Chemistry
1 answer:
melomori [17]3 years ago
4 0

Answer:

The chemical reactions in which oxidation and reduction takes place are called redox reaction.

Explanation:

CH4. + O2----> CO2. + H2O

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The answer is the first one. Hope this helps!!!!
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How do you calculate the number of neutrons in an atom? *
mrs_skeptik [129]

Answer: This means to find the number of neutrons you subtract the number of protons from the mass number.

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Select the correct answer.
Alenkasestr [34]

Answer:

D

Explanation:

The unit used to measure atomic mass is the atomic mass unit (amu). A single amu is equivalent to 1/12 the mass of an atom from the carbon-12 isotopIsotopes with different numbers of protons and neutrons will have an actual mass slightly different from the atomic mass calculated in atomic mass units.

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The molarity of a solution of 2.0 mol of NaOH in 5.OL of solution?
Gnesinka [82]

Answer:

<h2>0.4 M</h2>

Explanation:

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c =  \frac{n}{v}  \\

c is the molarity

n is the number of moles

v is the volume in L

From the question we have

c =  \frac{2}{5}  = 0.4 \\

We have the final answer as

<h3>0.4 M</h3>

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5 0
3 years ago
PbSO4 has a Ksp = 1.3 * 10-8 (mol/L)2.
Oduvanchick [21]

i. The dissolution of PbSO₄ in water entails its ionizing into its constituent ions:

\mathrm{PbSO_{4}}(aq) \rightleftharpoons \mathrm{Pb^{2+}}(aq)+\mathrm{SO_4^{2-}}(aq).

---

ii. Given the dissolution of some substance

xA{(s)} \rightleftharpoons yB{(aq)} + zC{(aq)},

the Ksp, or the solubility product constant, of the preceding equation takes the general form

K_{sp} = [B]^y [C]^z.

The concentrations of pure solids (like substance A) and liquids are excluded from the equilibrium expression.

So, given our dissociation equation in question i., our Ksp expression would be written as:

K_{sp} = \mathrm{[Pb^{2+}] [SO_4^{2-}]}.

---

iii. Presumably, what we're being asked for here is the <em>molar </em>solubility of PbSO4 (at the standard 25 °C, as Ksp is temperature dependent). We have all the information needed to calculate the molar solubility. Since the Ksp tells us the ratio of equilibrium concentrations of PbSO4 in solution, we can consider either [Pb2+] or [SO4^2-] as equivalent to our molar solubility (since the concentration of either ion is the extent to which solid PbSO4 will dissociate or dissolve in water).

We know that Ksp = [Pb2+][SO4^2-], and we are given the value of the Ksp of for PbSO4 as 1.3 × 10⁻⁸. Since the molar ratio between the two ions are the same, we can use an equivalent variable to represent both:

1.3 \times 10^{-8} = s \times s = s^2 \\s = \sqrt{1.3 \times 10^{-8}} = 1.14 \times 10^{-4} \text{ mol/L}.

So, the molar solubility of PbSO4 is 1.1 × 10⁻⁴ mol/L. The answer is given to two significant figures since the Ksp is given to two significant figures.

8 0
3 years ago
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