Which side lengths form a right triangle?

Mathematics

1 answer:

3241004551 [841]3 years ago

3 0

Answer: A

5,12,13 is a common Pythagorean triple, the second on the list after 3,4,5

B and C aren't on the list, and they would be if they were Pythagorean Triples, which is a list of natural number length sides (a,b,c) which satisfy the Pythagorean Theorem, a²+b²=c², making them the sides of a right triangle.

Let's verify:

5²+12² = 25+144 = 169 = 13² √

4²+4² = 16+16 = 32 ≠ 8² √

2²+3² = 4+9 = 13 ≠ 4² √

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Given logbM=3.2 logbN=-1.5 and logbP=2.4 find the value of logb(m^2N/p)

artcher [175]

The formulas:
$\log_a (xy)=\log_a x + \log_a y \\
\log_a (\frac{x}{y})=\log_a x - \log_a y \\
\log_a (x^n)n \log_a x$

Expand the expression:
$\log_b (\frac{m^2n}{p})=\log_b m^2 + \log_b n - \log_b p= 2 \log_b m+\log_b n - \log_b p$

Plug the values into the expression:
$\log_b m=3.2 \\ \log_b n=-1.5 \\ \log_b p=2.4 \\ \\
2 \log_b m+\log_b n - \log_b p=2 \times 3.2-1.5-2.4=6.4-3.9=2.5 \\ \\
\boxed{\log_b (\frac{m^2n}{p})=2.5}$

3 0

3 years ago

I need help please??? ):

andrew11 [14]

Answer:

n>4

Step-by-step explanation:

n-8 > -4

treat > as an equal sign and solve normally, first move -8 over and change to positive 8

n>-4+8

simplify

n>4