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evablogger [386]
4 years ago
8

Which values are solutions to the inequality below? Check all that apply.

Mathematics
1 answer:
ella [17]4 years ago
4 0

Answer:

A. B. D.E.

Step-by-step explanation:

I just put it in a calculator and see if the answer was smaller or equal to 6.

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A field is a rectangle with a perimeter of 1220 feet. The length is 100 feet more than the width. Find the width and length of t
rosijanka [135]
To start, let x represent the width and x+100 represent the length. Since the perimeter of a figure is the sum of all the measurements of the side which can be represented by (x+100)+(x+100)+x+x and since you know your perimeter is 1220, you can set the expression equal to 1220. This would look like this:
(x+100)+(x+100)+x+x=1220

Once you have done that, combine any like terms (combine terms with the same variables and raised to the same power together) which would simplify to this:
4x+200=1220

Now that you have your like terms simplified, subtract 200 from both sides to get 4x=1020 and finally, to solve for x, or find the width, divide both sides by 4 to get x=255.

Now that you have your width, now you must find your length as the question asks to find the dimensions of the rectangular field. To find the length, add 100 to the width, 255 since according to the information given, the length is 100 more than the width. When you add 100 to 255, you should get that your length is 355. 

Now that you have your length and width, you can conclude that the dimensions of the field is 255 by 355 feet, which is your answer :)
3 0
4 years ago
How can I factorise (2x cubed - 5x + 3) ?
PilotLPTM [1.2K]
2x^3-5x+3=2x^3-2x-3x+3\\\\=2x(x^2-1)-3(x-1)\\\\=2x\underbrace{(x^2-1^2)}_{use\ (*)}-3(x-1)\ \ \ |(*)\ a^2-b^2=(a-b)(a+b)\\\\=2x\underbrace{(x-1)}_{(**)}(x+1)-3\underbrace{(x-1)}_{(**)}\\\\=(x-1)[2x(x+1)-3]\\\\=(x-1)\underbrace{(2x^2+2x-3)}_{(***)}\\\\(***)\ 2x^2+2x-3\to a=2;\ b=2;\ c=-3\\\\x=\frac{b^2\pm\sqrt{b^2-4ac}}{2a}

therefore\\x=\frac{-2\pm\sqrt{2^2-4(2)(-3)}}{2(2)}=\frac{-2\pm\sqrt{4+24}}{4}=\frac{-2\pm\sqrt{28}}{4}=\frac{-2\pm\sqrt{4\cdot7}}{4}=\frac{-2\pm2\sqrt7}{4}\\\\=\frac{-1\pm\sqrt7}{2}\\\\so,\ the\ answer:\\\\(x-1)\cdot2\left(x-\frac{-1-\sqrt7}{2}\right)\left(x-\frac{-1+\sqrt7}{2}\right)\\\\=\boxed{(x-1)(2x+1+\sqrt7)\left(x+\frac{1-\sqrt7}{2}\right)}=\boxed{\frac{1}{2}(x-1)(2x+1+\sqrt7)(2x+1-\sqrt7)}
7 0
3 years ago
Read 2 more answers
Hi there! Three days ago I ordered 8 Neat cupcakes. This week I'd like 50% fewer than that.
Furkat [3]

Total cup cake ordered = 8

Percentage 'P' of a quantity x can be calculated using:

p/100 * x

Here,

P = 50%

x = 8

Put these values in formula.

50/100 * 8

=> 1/2 * 8

=> 4

So, the 50% fewer cupcakes would be (8 - 4) = 4 cupcakes.

4 0
1 year ago
The product of 1 1/2 and 2 is
Over [174]

Method 1:

Convert the mixed number to the improper fraction:

1\dfrac{1}{2}=\dfrac{1\cdot2+1}{2}=\dfrac{3}{2}

Make the product:

1\dfrac{1}{2}\cdot2=\dfrac{3}{2}\cdot2

<em>canceled 2</em>

=\dfrac{3}{\not2_1}\cdot\not2^1}=\boxed{3}

Method 2:

1\dfrac{1}{2}=1+\dfrac{1}{2}

1\dfrac{1}{2}\cdot2=\left(1+\dfrac{1}{2}\right)\cdot2

<em>use the distributive property a(b + c) = ab + ac</em>

(1)(2)+\left(\dfrac{1}{2}\right)(2)=2+1=\boxed{3}

7 0
3 years ago
Determine if the lim f(x) exists using the graph below.. If it does, find its value. If it does not,x 1explain why
Leno4ka [110]

The limit of a function f at a point a exists if:

\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)\begin{gathered} \text{ From the given image, the value of the left limit of f at x=1 } \\ \lim_{x\to a^-}f(x)\lt1 \end{gathered}

Also,

\begin{gathered} \text{ From the given image, the value of the right limit of f at x=1 } \\ \lim_{x\to a^+}f(x)\gt1 \end{gathered}

Therefore,

\lim_{x\to1^-}f(x)\lim_{x\to1^+}f(x)

Hence, the limit does not exist

8 0
1 year ago
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