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Feliz [49]
3 years ago
12

Positive and Negative ions attract each-other and form chemical __________

Chemistry
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

Changes

Explanation:

When positive and negative ions attract each other it fors a negative chemical changes

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calculate the volume occupied by 10g of propane gas, under normal conditions of temperature and pressure
andriy [413]

Answer:

5.5 L

Explanation:

First we <u>convert 10 g of propane gas</u> (C₃H₈) to moles, using its <em>molar mass</em>:

  • 10 g ÷ 44 g/mol = 0.23 mol

Then we <u>use the PV=nRT formula</u>, where:

  • P = 1 atm & T = 293 K (This are normal conditions of T and P)
  • n = 0.23 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • V = ?

1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

  • V = 5.5 L
3 0
3 years ago
26. All atoms area. positively charged, with the number of protons exceeding the number of electronsb, negatively charged, with
user100 [1]
(26) All atoms area...<span><span>with the number of protons equaling the number of electrons

</span>(27) </span>The particles that are found in the nucleus of an atom are...<span> protons and neutrons.

(28) </span>As a consequence of the discovery of the nucleus by Rutherford, which model of the atom is thought to be true?...<span>Protons. electrons, and neutrons are evenly distributed throughout the volume of the atom.

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7 0
3 years ago
Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t
Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution = 3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}

l = path length = 2.5 mm = 0.25 cm

I_o = incident light

I = transmitted light

\epsilon = molar absorptivity coefficient = 855dm^3mol^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)

\log \frac{I_o}{I}=0.6947

\frac{I_o}{I}=10^{0.6947}=4.951

If we consider I_o = 100

then, I=\frac{100}{4.951}=20.198

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light I_A = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100

\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%

Therefore, the percentage reduction in intensity is 79.80 %

3 0
4 years ago
C2H4(g) + H2(g) ----&gt; C2H6(g)
sertanlavr [38]
D because wants you add the equation it should increase temp but decrease the value in pressure
4 0
3 years ago
A reaction that absorbs energy
coldgirl [10]

Answer:

Endothermic Reaction

Explanation:

5 0
3 years ago
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