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Anna11 [10]
3 years ago
10

(W-4/9)(-2/3)=-4/5, How do I solve this problem?

Mathematics
2 answers:
STatiana [176]3 years ago
8 0
(W - 4/9)(-2/3) = -4/5......divide both sides by -2/3
W - 4/9 = (-4/5) / (-2/3)
W - 4/9 = -4/5 * -3/2
W - 4/9 = 6/5....add 4/9 to both sides
W = 6/5 + 4/9
W = 54/45 + 20/45
W = 74/45 or 1 29/45
Leto [7]3 years ago
6 0
(W-4/9)(-2/3)=-4/5
Divided -2/3 or multiply -3/2 to each side
(W-4/9)(-2/3)(-3/2)=-4/5(-3/2)
W-4/9=12/10
W-4/9=6/5
Add 4/9 to each side
W-4/9+4/9=6/5+4/9
W=54/45+20/45
W=74/45
W=1 29/45
Check:
(W-4/9)(-2/3)=-4/5
(74/45-4/9)(-2/3)=-4/5
(74/45-20/45)(-2/3)=-4/5
(54/45)(-2/3)=-4/5
-108/135=-4/5
-36/45=-4/5
-12/15=-4/5
-4/5=-4/5. As a result, W=74/45. Hope it help!
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The angle of depression from the top of a building to a point
AleksandrR [38]

The distance between point on the ground from the top of the building is 396 meter, if the building is 280 m high and The angle of depression from the top of a building to a point  on the ground is 45 degrees.

Step-by-step explanation:

The given is,

                 The angle of depression from the top of a building to a point  on the ground is 45 degrees.

                 Height of the building is 280 meter.

Step: 1

                 Given diagram is a right angled diagram,

                 For right angle triangle,

                              90° = 45° + 45°    

                                     = 90°  

                 Trignometric ratio,

                            sin ∅ = \frac{Opp}{Hyp}....................(1)

                For the above ratio take the bottom angle, that is angle of depression from the top of a building to a point  on the ground is 45 degrees.

                 Where, Opp side = 280 meters

                               Hyp side = x

                                           ∅ = 45°

                 Equation (1) becomes,

                                  sin 45° = \frac{280}{x}

                          0.70710678 =  \frac{280}{x}

                                            x =  \frac{280}{0.70710678}

                                            x = 395.979

               Distance between point on the ground from the top of the building,  x ≅ 396 meter                                                

                Trignometric ratio,

                                     cos ∅ = \frac{Adj}{Hyp}

                                   Cos 45 = \frac{Adj}{396}

                                         Adj = (0.70710678)(396)

              Bottom length, Adj = 280 meter

Result:

           The distance between point on the ground from the top of the building is 396 meter.

8 0
4 years ago
Mezclas de alimentos. Un chef repostero creó una solución de azúcar de 50 onzas constituida por 34% de azúcar con una solución d
Kay [80]

Answer:

Las cantidades empleadas para su preparación son: 15 onzas de solución al 20 % y 35 onzas de solución al 40 %.

Step-by-step explanation:

Podemos estimar la proporción de ingredientes mediante el siguiente promedio ponderado:

0.34= \frac{0.2\cdot m_{A} + 0.4\cdot m_{B}}{m_{A}+m_{B}} (1)

Donde:

m_{A} - Masa de la solución al 20 %, en onzas.

m_{B} - Masa de la solución al 40 %, en onzas.

Podemos simplificar la formula como sigue:

0.2\cdot x + 0.4\cdot (1-x) = 0.34 (2)

Donde x es la proporción de la solución al 20 % dentro de la solución final, sin unidades.

Ahora resolvemos para x en (2):

0.4-0.2\cdot x = 0.34

0.2\cdot x = 0.06

x = \frac{0.06}{0.2}

x = 0.3

Este resultado quiere decir que la solución al 34 % es el resultado de 30 % de la solución al 20 % y 70 % de la solución al 40 %. Si conocemos que la solución final tiene una masa de 50 onzas, entonces las cantidades empleadas para su preparación son: 15 onzas de solución al 20 % y 35 onzas de solución al 40 %.

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3 years ago
The length of a rectangle is 4 meters less than twice its width. The are of a rectangle is 70m^2. Find the dimensions of the rec
igomit [66]

Answer:

The length is 7 m

The width is 10 m

Step-by-step explanation:

length = x

width = 2x - 4

length * width = area

It is given that the area is 70 m^{2}

From there

x * (2x - 4) = 70

2x^{2} - 4x = 70

2x^{2} - 4x - 70 = 0

x^{2} - 2x - 35 = 0

Now we have a quadratic equation, which is  ax^{2} + bx + c = 0, where a \neq 0

In this equation a = 1, b = -2 and c = -35

Discriminant (D) formula is b² - 4ac

D = -2^{2}  - 4 * 1 * (-35) = 144 > 0

This discriminant is more than 0, so there are two possible x

Their formulas are  \frac{- b - \sqrt{D}  }{2a} and \frac{- b + \sqrt{D}  }{2a}

x_{1} =  \frac{- (-2) - \sqrt{144} }{2} = -5 < 0 (the length of the rectangle has to be more than 0, so we don't use this x)

x_{2} = \frac{- (-2) + \sqrt{144} }{2} = 7 > 0 (this one is right)

Calculating the dimensions

length = x = 7 (m)

width = 2x - 4 = 2 * 7 - 4 = 10 (m)

8 0
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Answer:

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