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Ugo [173]
4 years ago
14

5x squared + 14 x - 3 equals 0​

Mathematics
2 answers:
Ivahew [28]4 years ago
4 0

Answer:

x= 1/5 and x= -3 or (-3, 0) and (1/5, 0)

Step-by-step explanation:

I think the easiest way would be the snowflake method.

you have to find 2 numbers that would multiply to get -15, but add to get 14, which would be 15 and -1.

then you would have (5x-1)(5x+15)

5x+15 would simplify to:  x+3

your equation would then be:

(5x-1)(x+3)

make both of those equal to "0", and solve for both.

5x-1=0 and x+3=0

hodyreva [135]4 years ago
3 0

Answer:5x²+14x-3=0

5x²+15x-x-3=0

5x(x+3)-x-3=0

5x(x+3)-(x+3)=0

(X-3)×(5x-1)=0

X1= x-3=-3

X2=1/5

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Solve the nonhomogeneous differential equation y′′+25y=cos(5x)+sin(5x). Find the most general solution to the associated homogen
Marrrta [24]

Answer:

y(x)=c_1cos(5x)+c_2sin(5x)+0.1xsin(5x)-0.1xcos(5x)

Step-by-step explanation:

The general solution will be the sum of the complementary solution and the particular solution:

y(x)=y_c(x)+y_p(x)

In order to find the complementary solution you need to solve:

y''+25y=0

Using the characteristic equation, we may have three cases:

Real roots:

y(x)=c_1e^{r_1x} +c_2e^{r_2x}

Repeated roots:

y(x)=c_1e^{rx} +c_2xe^{rx}

Complex roots:

y(x)=c_1e^{\lambda x}cos(\mu x) +c_2e^{\lambda x}sin(\mu x)\\\\Where:\\\\r_1_,_2=\lambda \pm \mu i

Hence:

r^{2} +25=0

Solving for r :

r=\pm5i

Since we got complex roots, the complementary solution will be given by:

y_c(x)=c_1cos(5x)+c_2sin(5x)

Now using undetermined coefficients, the particular solution is of the form:

y_p=x(a_1cos(5x)+a_2sin(5x) )

Note: y_p was multiplied by x to account for cos(5x) and sin(5x) in the complementary solution.

Find the second derivative of y_p in order to find the constants a_1 and a_2 :  

y_p''(x)=10a_2cos(5x)-25a_1xcos(5x)-10a_1sin(5x)-25a_2xsin(5x)

Substitute the particular solution into the differential equation:

10a_2cos(5x)-25a_1xcos(5x)-10a_1sin(5x)-25a_2xsin(5x)+25(a_1xcos(5x)+a_2xsin(5x))=cos(5x)+sin(5x)

Simplifying:

10a_2cos(5x)-10a_1sin(5x)=cos(5x)+sin(5x)

Equate the coefficients of cos(5x) and sin(5x) on both sides of the equation:

10a_2=1\\\\-10a_1=1

So:

a_2=\frac{1}{10} =0.1\\\\a_1=-\frac{1}{10} =-0.1

Substitute the value of the constants into the particular equation:

y_p(x)=-0.1xa_1cos(5x)+0.1xsin(5x)

Therefore, the general solution is:

y(x)=y_c(x)+y_p(x)

y(x)=c_1cos(5x)+c_2sin(5x)+0.1xsin(5x)-0.1xcos(5x)

6 0
3 years ago
What is the equation of the graphed linear model?<br><br><br><br> y = <br> x +
timofeeve [1]

Answer:

y = - 2x + 110

Step-by-step explanation:

The equation of a line in slope- intercept form is

y + mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 110) and (x₂, y₂ ) = (20, 70) ← 2 points on the line

m = \frac{70-110}{20-0} = \frac{-40}{20} = - 2

the line crosses the y- axis at (0, 110) ⇒ c = 110

y = - 2x + 110 ← equation of line

7 0
4 years ago
Simplify the following expression into the form a + bi, where a and b are rational numbers.
vagabundo [1.1K]
The answer is -16 - 10i.

Using the distributive property on the first part, we have:
-2i*7--2i*4i + (3+i)(-2+2i)
-14i+8i² +(3+i)(-2+2i)

Using FOIL on the last part,
-14i+8i²+(3*-2+3*2i+i*-2+i*2i)
-14i+8i²-6+6i-2i+2i²
-10i+8i²-6+2i²

Since we know that i = -1,
-10i+8(-1)-6+2(-1)
-10i-8-6-2
-16-10i
7 0
3 years ago
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What is 12 3/5 divided 2 1/10?
raketka [301]

Answer:

The answer is six

Step-by-step explanation:

12 3/5 = 63/5

2 1/10 = 21/10

63/5 divided by 21/10 is equal to 63/5 multiplied by 10/21 which is equal to 630/105 = 6 <-- answer

7 0
3 years ago
What is the value for x? Enter your answer in the box.
Lynna [10]

angles BAC and BCA are equal = 69

69 +69 = 138

angles in a triangle =180

180-138 = 42

5x + 2 = 42

5x = 40

x = 8

8 0
4 years ago
Read 2 more answers
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