Answer:
Exact answer not possible: See below.
Step-by-step explanation:
The total that Tammy would pay is the sum of 2A and 5B, where A and B are the number of candies costing $2 and $5, respectively. Therefore:
2A + 2B = Total Spent
We are told Tammy spent <u>at least</u> $75, which can be written as "Total Spent > $75."
The equation becomes 2A + 5B > 75
Rearranging:
2A + 5B > 75
2A > 75 - 5B
A > (75 - 5B)/2
To find the maximum of the candy A bought, one can try different values of A and B that result in a total of at least $75. If the amount spent were $75 exactly, a solution would be 35 A (for $70), leaving $5 for 1 candy B. But we don't know the exact amount. The problems states "at least $75." As far as we know, Tammy may have spent $105, $405, $1,005, or even $4,005 (200 A and 1 B). One cannot pick a maximum simply since the maximum spent is not defined. The next possible value above $75 would be $77, which represents 36 A and 1 B candies.
Answer:
A square root parent function
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
The table
First, we calculate the amount of schools
Solving (a): Probability of 75+ computers.
From the given table, schools with 75 or more computers have the population of:
The probability is calculated as:
Solving (b): Probability of less than 75 computers.
From the given table, schools with less than 75 computers have the population of:
The probability is calculated as:
Solving (c): Probability of less than 10 computers.
From the given table, schools with less than 100 computers have the population of:
The probability is calculated as:
Answer:
Your welcome
Step-by-step explanation:
(Pls tell me if the answer did not show it has been doing that to me)
Answer:
The answer would be 10/16.
Hope this helps!
Brianliest?
