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3 years ago

Fifteen more than four times a number is equal to the difference between 191 and four times the number. Find the number.

Mathematics

1 answer:

Semenov [28]3 years ago

5 0

Answer:

The number would be 22.

Step-by-step explanation:

In order to solve for the number, we need to make both statements into numerical statements.

Fifteen more than four times a number = 15 + 4x

difference between 191 and four times the number = 191 - 4x

Now we set them equal to each other.

15 + 4x = 191 - 4x -----> Add 4x to each side

15 + 8x = 191 ------> Subtract 15 from both sides

8x = 176 -------> Divide by 8

x = 22

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Factor the polynomial completely

aliina [53]

We have $2x^2-8$ .

First let us factor the 2 to obtain,

$2(x^2-4)$

We can now see clearly that the expression inside the parentheses is a difference of two squares.

We now write the 4 as 2². So that we obtain the expression,

$2(x^2-2^2)$

Recall that

$a^2-b^2=(a+b)(a-b)$

Hence our expression becomes,

$2(x+2)(x-2)$

Therefore, when factored completely,

$2x^2-8=2(x+2)(x-2)$

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3 years ago

The chart below describes the speed of four runners. Which runner is the fastest?

tensa zangetsu [6.8K]

Answer:

Runner B

Step-by-step explanation:

speed = distance ÷ time

Runner A: 1 ÷ 8 = 0.125m/ms

Runner B: 2 ÷ 10 = 0.2m/ms

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6 0

2 years ago

Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

$(26)x = 1$

$(50)x = 1$

and:

$(2^6)^x = 1$

$(5^0)^x = 1$

Solving: $(26)x = 1$ and $(50)x = 1$

$(26)x = 1$

Divide both sides by 26

$x = \frac{1}{26}$

$(50)x = 1$

Divide both sides by 50

$x = \frac{1}{50}$

Solving $(2^6)^x = 1$ and $(5^0)^x = 1$

$(2^6)^x = 1$

Express 1 as 2^0

$(2^6)^x = 2^0$

Remove bracket

$2^{6x} = 2^0$

Cancel out 2

$6x = 0$

Divide both sides by 6

$x = \frac{0}{6}$

$x = 0$

$(5^0)^x = 1$

Express 1 as 5^0

$(5^0)^x = 5^0$

Cancel out 5^0

$x = 1$

8 0

3 years ago

I think it is c, am I right?

Sphinxa [80]

Answer:

Yes

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

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Svetradugi [14.3K]

Answer:

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