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ratelena [41]
3 years ago
7

Can someone please help asap!!! tysm

Physics
1 answer:
Maru [420]3 years ago
7 0

the answer is 0m/s२.

Explanation:

Because when the object is changing position at a constant velocity,the acceleration is 0m/s२.

I hope it'll help u.

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Students can take the aspire test in ninth and grade
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Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is
Anestetic [448]

The electrical force between the two charges can be calculated as +1.8×10⁻² N and its repulsive.

To find the electrical force, distance = 2 meters

charge q1 = 2×10⁻⁶ C

charge q2 = 4×10⁻⁶ C

<h3>Define coulomb's law and solve with formula.</h3>

         The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.

Formula can be written as,

          F = K ( q1q2 / r² )

F - electric force

k - Coulomb constant

q1, q2 - charges

r - distance of separation

Substituting the values in the formula,

         F = 9 × 10⁹ Nm²/C² ( (2×10⁻⁶ C ×  4×10⁻⁶ C) / (2²))

            = 0.0179751

         F = 1.8 × 10 ⁻² N.

As both the charges q1 and q2 are positive, the charges gets repulsive.

SO, the correct answer is Option A.

Learn more about coulomb's law,

brainly.com/question/506926

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Which of these is a function of the digestive system ?
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The filament in an incandescent light bulb is made from tungsten. The resistivity of tungsten = 5.6e-8 Ω*m. The radius of the tu
sashaice [31]

Answer:

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Explanation:

Given:

Resistivity ρ = 5.6e-8 Ωm

Radius r = 0.045 mm =\frac{0.045}{1000} = 4.5 x 10⁻⁵ m

Voltage V = 120V

Current I = 1.24A

From Ohm's law, R = \frac{V}{I}

                            R = \frac{120}{1.24}

                            R = 96.77 Ω

Resistivity = (Resistance × Area)/ length

      ρ = (RA)/L

Therefore, the length of a wire is given by;

       L = (RA)/ρ

Calculating the area A of the wire;

       A = πr²

       A = π × (4.5 x 10⁻⁵)²

       A = 6.36 x 10⁻⁹ m²

Substituting area of the wire A =  6.36 x 10⁻⁹ m² into the equation of the length of wire

       L = (96.77 × 6.36×10⁻⁹ ) / 5.6×10⁻⁸

       L = 10.9977m

       L = 11m (approximately)

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