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Firlakuza [10]
3 years ago
10

This graph indicates that the kinetic energy of an object is increasing. What is the most reasonable explanation for this observ

ation?
A) The object's mass has doubled.
B) The object's velocity doubled.
C) The object's velocity has quadrupled.
D) The object's velocity and mass doubled.

Physics
1 answer:
soldi70 [24.7K]3 years ago
5 0

B) The object's velocity doubled.

Explanation:

The graph is missing: find it in attachment.

The kinetic energy of an object is the energy possessed by the object due to its motion. It is calculated as

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is the velocity of the object

We notice that:

  • The  kinetic energy is directly proportional to the mass
  • The kinetic energy is proportional to the square of the velocity

In the graph, one of the two quantities (either mass or speed) is represented on the x-axis, while the quantity on the y-axis is the kinetic energy.

First of all, we notice that the relationship is not linear: this means that the quantity on the x-axis cannot be the mass, so it must be the velocity.

Moreover, we notice that when the quantity on the x-axis increases from 1 to 2 (so, it doubles), the kinetic energy increases by a factor of 4. This means that the object's velocity has doubled, therefore

B) The object's velocity doubled.

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

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A metal ball has a net charge of 4.5x10-7 C
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a) the number of protons is 2.81\cdot 10^{12} more than the electrons

b) 4.69\cdot 10^{-15} kg

Explanation:

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This electric charge is given by the algebraic sum of the charge of the protons and of the charge of the electrons.

The charge of one proton is:

q_p =+e= +1.6\cdot 10^{-19}C

While the charge of one electron is

q_e = -e=-1.6\cdot 10^{-19}C

So the net charge on the metal ball will be given by

Q=N_p q_p + N_e q_e = (N_p -N_e)e

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N_p-N_e=\frac{Q}{e}=\frac{4.5\cdot 10^{-7}}{1.6\cdot 10^{-19}}=2.81\cdot 10^{12}

This means that the number of protons is 2.81\cdot 10^{12} more than the electrons.

b)

In this case, we want to make the ball neautral, so we have to remove a net charge of Q' such that the new charge is zero:

Q-Q'=0

This implies that the charge that we must remove is

Q'=Q=4.5\cdot 10^{-7}C

To do that (and to make the ball losing mass at the same time), we have to remove protons, since they have positive charge.

The number of protons that must be removed is:

N_p = \frac{Q'}{q_p}=\frac{4.5\cdot 10^{-7}}{1.6\cdot 10^{-19}}=2.81\cdot 10^{12}

The mass of one proton is

m_p = 1.67\cdot 10^{-27}kg

Therefore, the total mass that must be removed from the ball is

M=m_p N_p = (1.67\cdot 10^{-27})(2.81\cdot 10^{12})=4.69\cdot 10^{-15} kg

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