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4 years ago

a red ball moves horizontally in a 30 m long tube what is the displacement of the red ball between 0s and 24s?

Physics

1 answer:

gayaneshka [121]4 years ago

7 0

Answer:

30 metres.

Explanation:

Given that a red ball moves horizontally in a 30 m long tube.

Displacement is the distance travelled in a specific direction. It has both magnitude and direction.

Since the motion is horizontal, it moves is a certain direction.

Within the stipulation of time, the displacement will be the distance covered in the horizontal direction which is 30 metres.

Therefore, the displacement of the motion of the red ball is 30 metres.

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Engineers tasked with building a car bumper need high-quality plastic that is readily available. They found the material polycar

jenyasd209 [6]

Answer:

The material must be durable (quality of the material requirement)

Explanation:

The design criteria set for the materials used for technological design are;

1) The materials should be affordable (less costly)

2) The materials should be last for a long duration (high durability)

3) The material should be readily available (easily sourced)

Therefore, given that the engineers initially had the criteria for the required plastic to be of high quality and to be readily available, and that the poly-carbonate they found is long lasting and not too costly, the criteria met that was set initially was the quality criteria of durability.

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3 years ago

Read 2 more answers

the gas in a balloon has P=100000 pa and v=0.0279 m^3. if the pressure increases to 120000 pa at constant temperature, what is t

mash [69]

Answer:

New volume of the baloon is 0.02325m^3

Explanation:

To answer this question we need to know the ideal gas law, which says:

p•V = n•R•T

p is pressure, V is volume, n is amount of substance (in moles), R is constant value and T is temperature.

Since it's stated that n and T are constant, and we know that R is a constant too, that means that p•V = constant value. Basically, that means that p1•V1 (pressure and volume before the pressure increase) equals to p2•V2 (pressure and volume after the pressure increase).

That means that:

100000 Pa • 0.0279 m^3 = 120000 Pa • V2. Next, V2= 100000•0.0279/120000. So, V2=0.02325m^3.

6 0

3 years ago

Read 2 more answers

Suppose an object in freefall is dropped from a building it’s starting velocity is 0m/s. Ignoring the facts of air resistance wh

Alja [10]

v = v₀ + at

v = final speed, v₀ = initial speed, a = acceleration, t = elapsed time

Given values:

v₀ = 0m/s (starts from rest), a = 9.81m/s², t = 3s

Plug in and solve for v:

v = 0 + 9.81(3)

v = 29.4m/s

3 0

3 years ago

Q1: A runner is jogging in a straight line at a steady vr= 6.8 km/hr. When the runner is L= 2.4 km from the finish line, a bird

serious [3.7K]

Answer:

Q1: 3.2km

Q2: 4.8K

Explanation:

Q1:

So db is the distance of bird, and dr is the distance of runner

db = 2vr and the distance of bird is going to be 2 times greater than the runner.

formulas: db = 2vr & db = 2dr

db = 2dr
L + (L - x) = 2x
2L - x = 2x
2L = 3x
x = $\frac{2}{3}$ L

Insert it in x = $\frac{2}{3}$ L

$\frac{2}{3}$ (2.4km) = 1.6km

Now we use formula db = 2dr

db = 2L - x
db = 2(2.4km) - 1.6km
db = 3.2km

Q2:

Formulas: Vr = L /Δt & Vb = db/Δt

Vr = L/ Δt ⇒ Δt = $\frac{L}{Vr}$
$\frac{2.4km}{6.8km/hr}$
$\frac{6}{17}hr$

(Km cancel each other)

Vb = db/Δt ⇒ db = VbΔt
13.6km/hr $(\frac{6}{17}hr )$
4.8km

(hr cancel each other)

Hope it helps you :)

6 0

3 years ago

Perpendicular parking spaces require turning at a ______-degree angle.

Archy [21]

Perpendicular means at 90 degree angle. so,
Perpendicular parking spaces require turning at a 90 degree angle.

When you are going to park perpendicularly, you need a distance of 7 to 8 feet from the vehicle you are parking next to, and when you are parking parallel, you need 5 feet distance from the vehicle you are parking next to.

7 0

3 years ago