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zzz [600]
3 years ago
6

A golfer hits a shot to a green. The ball leaves the club at a speed of 20 m/s at an angle 32° above the horizontal. It rises to

its maximum height and then falls down to the green. What is the speed of the ball at maximum height? Ignore air resistance.
Physics
1 answer:
Daniel [21]3 years ago
4 0

Answer:

16.96 m/s

Explanation:

It is the case of projectile motion in which the projectile fires from the ground and again it hit the ground.

The angle of projection is 32 degree and the velocity of projection is 20 m/s

he velocity at the maximum height is equal to the horizontal component of velocity which always remains constant as there is no acceleration along x axis.

Velocity at the highest point = u Cos 32 = 20 x Cos 32 = 16.96 m/s

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A force is a push or pull upon an object resulting from the objects interaction with another object

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A volcano erupts spewing ash into the air and sending lava flowing down the side of the mountain. Looking at the image explain h
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11) A sled is initially given a shove up a frictionless 35º incline. It reaches a maximum height of 2.5
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Answer:

7 m/s

Explanation:

To solve this problem you must use the conservation of energy.

K1 +U1=K2+U2

That math speak for, initial kinetic energy plus initial potential energy equals final kinetic energy plus final potential energy.

The initial PE (potential energy) is 0 because it hasn't been raised in the air yet. The final KE (kinetic energy) is 0 because it isn't moving. This gives the following:

KE1= \frac{1}{2}mv^{2}}

PE2=mgh

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Solve for v

v=\sqrt{2gh}

Input known values and you get 7 m/s.

5 0
2 years ago
A 24-V battery is powering a light bulb with a resistance of 3.0 ohms. What is the current flowing through the bulb? A) 7.20 A B
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3 0
3 years ago
Two moles of an ideal monatomic gas are at a temperature of 345 K. Then, 2250 J of heat is added to the gas, and 870 J of work i
Lapatulllka [165]

Answer: The final temperature is 470K

Explanation: Using the relation;

Q= ΔU +W

Given, n = 2mol

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T2 =Final temperature =?

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ΔU=3/2 × 2 ×8.314 (T2 - 345)

ΔU=24.942(T2-345)

Therefore Q = 24.942(T2-345)+ (-870)

2250=24.942(T2-345)+ (-870)

125.09=(T2-345)

T2 =470K

Therfore the final temperature is 470K

5 0
2 years ago
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