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zzz [600]
3 years ago
6

A golfer hits a shot to a green. The ball leaves the club at a speed of 20 m/s at an angle 32° above the horizontal. It rises to

its maximum height and then falls down to the green. What is the speed of the ball at maximum height? Ignore air resistance.
Physics
1 answer:
Daniel [21]3 years ago
4 0

Answer:

16.96 m/s

Explanation:

It is the case of projectile motion in which the projectile fires from the ground and again it hit the ground.

The angle of projection is 32 degree and the velocity of projection is 20 m/s

he velocity at the maximum height is equal to the horizontal component of velocity which always remains constant as there is no acceleration along x axis.

Velocity at the highest point = u Cos 32 = 20 x Cos 32 = 16.96 m/s

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Explanation:

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Based on the reading which statement is FALSE?
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An object is 15 cm in front of a diverging lens with a
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A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

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Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

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As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

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This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

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