Answer:
The acceleration of the refrigerator is 
Explanation:
The expression of the equation of the net force acting on the refrigerator is as follows;
F-f= ma
Here, F is the applied force, f is the force of friction, m is the mass and a is the acceleration.
It is given in the problem that you're having a hard time pushing a refrigerator having mass 355 kg across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N.
Put F= 993, f= 973 N and m = 355 kg in the above expression of the equation to calculate the acceleration of the refrigerator.
993 - 973 = (355)a
20 = 355 a
Therefore, the acceleration of the refrigerator is .
<u>Statement</u><u>:</u>
Jane does 5 joules of work when she closes her bedroom window. She applies a force of 6 newtons to do the job.
<u>To </u><u>find </u><u>out:</u>
The displacement of the window when she pulled it.
<u>Solution</u><u>:</u>
- Work done (W) = 5 J
- Force (F) = 6 N
- Let the displacement of the window be s.
- We know, the formula of work done, i.e., W = Fs
- Putting the values in the above formula, we get
- 5 J = 6 N × s
- or, s = (5 ÷ 6) m
- or, s = 0.83 m
<u>Answer</u><u>:</u>
She pulls the window by 0.83 m.
Hope you could understand.
If you have any query, feel free to ask.
Answer: I showed you all calculation . You did not attach any graph to question .
Explanation:
Lets first find Velocity
Vr=o m/s
Ve=?
a=1m/s²
t=2s
----------
a=(Vr-V)/t
1m/s²=Vr-0m/s/2s
2m/s=Vr
Lets find the time neeeded to stop :
a=1m/s²
Vs=2m/s
Vf=0m/s
a=(Vf-Vs)/t
t*1m/s²=2m/s
t=2 s
Definitely not the last 2. My bet is on the first option. If it is wrong don't hit me please...
