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4 years ago

I need help! Please! This is big dumb. And I am feeling big dumb Will mark brainiest!

Physics

2 answers:

Vladimir [108]4 years ago

4 0

Please don't run yourself down ! You are not dumb ! You are a school-boy, using a computer, to access the Internet, implement duplex digital communication, and answer a question on Sir Isaac Newton's laws of motion. I'm pretty sure that your parents and grandparents could never do most of that !

Now I'll SHOW you that you're only overthinking this. If you didn't practically INVITE it to scare you, it couldn't do that.

The question is: When you push a 0.65 kg ball with 125 Newtons of force, what is the ball's acceleration ?

That's the question. You have no idea how to get acceleration out of mass and force. You kinda remember that there was some kinda formula to calculate it with, but there's no chance that you remember the formula.

Now SIT UP in your chair, turn off your phone and the music, LOOK at the problem, READ it, and ALLOW your BRAIN to warm up.

READ the first line. It says USE THIS FORMULA . What are the letters in the formula ?

-- ' a ' ... that's acceleration; that's what you have to find.

-- ' F ' ... that's Force; you know it; it's 125 Newtons.

-- ' m ' ... that's mass; you know it; it's 0.65 kg .

What would happen if you write 125 in place of the 'F', write 0.65 in place of the 'm', and divide them because it's written in a fraction ? You'd get a single number. Then the formula would say ' acceleration = the number '.

Would it be the correct number for acceleration ? I don't know. But who cares ! The problem says "Use this formula". So the right answer is whatever number you get when you use this formula.

It so happens that the formula IS the correct one, because it comes from Newton's second law of motion; eventually, you'll need to know this. But right now, to answer the question and solve the problem, all you have to do it USE THIS FORMULA, and see if the number you get is one of the choices.

Don't overthink these things. They can't scare you if you don't let them.

Gelneren [198K]4 years ago

4 0

Answer:

Its C, the answer is C

Explanation:

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3 years ago

A What quantity is equal to

natulia [17]

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Option B is correct

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3 years ago

Speed is an important component of which of the following sports? A. tennis B. soccer C. swimming D. all of the above Please sel

sladkih [1.3K]

D. all of the above

Explanation:

The best answer from the choices is option D all of the above.

Speed is a key component aspect of almost all sport.

What is speed:

Speed is the rate of change of distance with time;

Speed = $\frac{distance}{time}$

distance is the path taken by a body

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In tennis, speed is very essential and critical same as soccer and swimming. In fact, sports with more speed have very good advantage at excelling.

learn more:

Speed brainly.com/question/10435836

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4 years ago

Read 2 more answers

show answer Incorrect Answer 33% Part (b) Find the radius of curvature, in meters, of the path of a proton accelerated through t

timofeeve [1]

The question is incomplete. Here is the complete question.

Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.65T.

part (a): What is the potential difference, in volts, required in the first part of the experiment to accelerate electrons to a speed of 6.2 x 10⁷m/s?

part (b): Find the radius of curvature, in meters, of the path of a proton accelerated trhough this same potential after the proton crosses into the region with the magnetic field.

part (c) what is the ratio of the radii of curvature for a proton and an electron traveling through this apparatus?

Answer: (a) V = - 109.44 x 10² V

(b) $r_{p}=$ 9.95 x 10⁻¹ m

Explanation: (a) Potential difference is defined as the energy a charged particle has between two points in a circuit. It is calculated as

$\Delta V=\frac{pe}{q}$

where

pe is potential energy

q is charge

and its unit is joule/coulomb of Volts (V).

To determine potential difference required to accelerate a particle, we have to use the principle that the total energy of a system is conserved and one transforms into the other.

In this case, potential energy is transformed in kinetic energy:

pe = V.q

ke = $\frac{1}{2}m.v^{2}$

$V.q=\frac{1}{2} m.v^{2}$

$V=\frac{m.v^{2}}{2q}$

Calculating:

$V=\frac{9.11.10^{-31}(6.2.10^{7})^{2}}{2(-1.6.10^{-19})}$

V = $-109.44$ x 10²V

Potential difference of an electron to have speed of 6.2x10⁷m/s is $-109.44$ x 10²V.

(b) A particle has a circular motion when there is a magnetic force acting on it.

Velocity and magnetic force are always perpendicular to each other. Because of that, there is no work on the particle and so, kinetic energy and speed are constant. Since magnetic force supplies centripetal force:

$F_{mag} = F_{c}$