S=d/t ⇒d=s*t
s=speed
d=distance
t=time
The first train :
d=x
x=70 miles/h*t ⇒ x=70t (1)
The second train
d=360 miles - x
360 miles - x=80 miles/h*t ⇒360-x=80t ⇒ x=360-80t (2)
therefore, with the equations (1) and (2) we have a systeme of equations:
x=70t
x=360-80t
we can solve this system of equations by equalization method.
70t=360-80t
70t+80t=360
150t=360
t=360/150=2.4 (≈2 hour 24 minutes)
Answer: the first train meet with the second train in 2 hour 24 minutes.
Because 2 squares equal a meter u have to do four up down one. (Front elevation)
Then just four by one square on second row down(side elevation)
Hey there! :)
6n + 12 = 6
Isolate our given variable.
We can do this by subtracting both sides by 12.
6n + 12 - 12 = 6 - 12
Simplify.
6n = -6
Divide both sides by 6.
6n ÷ 6 = -6 ÷ 6
Simplify.
n = -1
~Hope I helped!~
Answer:
Part A:
When the temperature was cool the more longboards got rented. Most of the longboards got rented when it was 10C out.
Part B:
The line would fit at the coordinates: (5,0) (15.5) (24,10) (30,13) (35,15) (45,20) (55,25) (60,27)
