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Sladkaya [172]
3 years ago
12

What is the standard form for 5.948x10

tle="5.948 \times 10{5} " alt="5.948 \times 10{5} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
vlabodo [156]3 years ago
5 0

Answer:

594,800

Step-by-step explanation:

work is shown and pictured

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Miranda found out that there are 20 drops in 11 mL of medicine. She measured 15 drops of medicine into a measuring cup. How many
andreyandreev [35.5K]

Answer: Her measuring cup has 8.25 mL of medicine.

Step-by-step explanation:

As per given,

In 11 mL of medicine, there are 20 drops.

That means quantity in 1 drop = \dfrac{11}{20} mL

Now , the quantity in 15 drops = 15 x quantity in 1 drop

= 15\times\dfrac{11}{20}

=\dfrac{33}{4}

= 8.25 mL

Hence, her measuring cup has 8.25 mL of medicine.

6 0
3 years ago
Geometry)) Find the value of x
Harlamova29_29 [7]

Answer:

\tt x=14

Step-by-step explanation:

\tt 6x+6=90

\tt 6x+6-6=90-6

\tt 6x=84

\tt \cfrac{6x}{6} =\cfrac{84}{6}

\tt x=14

~

8 0
2 years ago
The times to process orders at the service counter of a pharmacy are exponentially distributed with mean 1 0 minutes. If 100 cus
g100num [7]

Answer:

Therefore,  the probability that at least half of them need to wait more than 10 minutes is <em>0.0031</em>.

Step-by-step explanation:

The formula for the probability of an exponential distribution is:

P(x < b) = 1 - e^(b/3)

Using the complement rule, we can determine the probability of a customer having to wait more than 10 minutes, by:

p = P(x > 10)

  = 1 - P(x < 10)

  = 1 - (1 - e^(-10/10) )

  = e⁻¹

  = 0.3679

The z-score is the difference in sample size and the population mean, divided by the standard deviation:

z = (p' - p) / √[p(1 - p) / n]

  = (0.5 - 0.3679) / √[0.3679(1 - 0.3679) / 100)]

  = 2.7393

Therefore, using the probability table, you find that the corresponding probability is:

P(p' ≥ 0.5) = P(z > 2.7393)

<em>P(p' ≥ 0.5) = 0.0031</em>

<em></em>

Therefore,  the probability that at least half of them need to wait more than 10 minutes is <em>0.0031</em>.

8 0
3 years ago
Please help me here dudes and dudettes
BabaBlast [244]

Answer:

what!!!!!!!!!!!!!!!!!! so only for dudesssssssss

6 0
3 years ago
Jack crawled 3 ft and Christine crawled 3⁄4 the distance Jack crawled. If you add the distance they each crawled together, what
LUCKY_DIMON [66]
Christine crawled:
3 ft* (3/4)= 2.25 ft.

3 ft+ 2.25 ft= 5.25 ft

We already know that 1 ft= 12 in.

5.25 ft* (12in/ 1 ft)= 63 in.

The total distance the two children crawled together is 63 in~
5 0
3 years ago
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