6358 was rounded to the nearest one.<br><br> What is the lower bound?

How many times does 85 go into 886

Allushta [10]

According to a calculator it says 10.4235941176471 Have a good day! Brainliest Answer please ?

3 0

3 years ago

if accrotime guarantees a full refund on any defective watch for 2 years after purchase, what percentage of total

adell [148]

Answer:

A. 0.62%

B. 28 months

Step-by-step explanation:

A. Calculation for what percentage of total production will the company expect to replace

Let x represents the distribution of life times

Let mean be 34 months

Let standard deviation be 4 months.

Based on the information the full refund on any defective watch for 2 years will represent 24 months (2 years *12 months).

First step

P(X<24)

= p(x-mean/ standard deviation< 24-34/4)

= p(z< -10/4)

=P(z<-2.5)

Second step is to Use the excel function to find NORMSDIST(z) of P(z<-2.5)

NORMSDIST(z)=0.62%

Therefore the percentage of total production will the company expect to replace will be 0.62%

B. Calculation for how much the guarantee period should be

First step

P(X<x)=0.06

P(x-Mean/Standard deviation < x-34/4) = 0.06

Second Step is to Use excel function

P(z<x-34/4) = (Normsinv(0.06)

x-34/4 = -1.555

Now let calculate how much the guarantee period should be

x = -6.22+34 months

x = 27.78

x = 28 months (Approximately)

Therefore the guarantee period should be 28 months

4 0

3 years ago

Dwayne starts assembling marketing packets at 11 a.m. Ashlie starts assembling marketing packets at 11:30 a.m. and assembles at

musickatia [10]

Answer:

Option A = 75 is the best option

Step-by-step explanation:

It took Ashlie 2.5 hours (11:30 am - 2pm) to assemble the marketing packets

Rate = Number of jobs done/Time taken = 90 packages/hr

Number of jobs done = Rate * Time taken = 90 * 2.5 = 225 packages.

Dwayne has assembled the same number of packages = 225 (as reported in the question),

It took Ashlie 2.5 hours (11 am - 2pm)

Then, his work rate is calculated as: Number of jobs done/Time taken = 225 packages/3 hours = 75

Thus, option A = 75 is the best option

4 0

3 years ago

5 more than 20 what is 5 more than 35 <br> What is five more than 50 what is five more than 85

Nadya [2.5K]

5+20=25
5+35=40
5+50=55
5+85=90

6 0

4 years ago

Read 2 more answers

(a) Suppose anxn has finite radius of convergence R and an ≥ 0 for all n. Show that if the series converges at R, then it also c

valina [46]

Answer:

a) See the proof below.

b) $\sum \frac{(-x)^n}{n}$

Step-by-step explanation:

Part a

For this case we assume that we have the following series $\sum a)n x^n$ and this series has a finite radius of convergence $R$ and we assume that $a_n \geq 0$ for all n, this information is given by the problem.

We assume that the series converges at the point $x= R$ since w eknwo that converges, and since converges we can conclude that:

$\sum a)n R^n < \infty$

For this case we need to show that converges also for $x=-R$

So we need to proof that $\sum a_n (-R)^n < \infty$

We can do some algebra and we can rewrite the following expression like this:

$\sum a_n (-R)^n = \sum (-1)^n a)n R^n$ and we see that the last series is alternating.

Since we know that $\sum a_n x^n$ converges then the sequence { $a_n R^n$ } must be positive and we need to have $lim_{n\to \infty} a^n R^n = 0$

And then by the alternating series test we can conclude that $\sum a_n (-R)^n$ also converges. And then we conclude that the power series $a_n x^n$ converges for $x=-R$ ,and that complete the proof.

Part b

For this case we need to provide a series whose interval of convergence is exactly (-1,1]

And the best function for this $\frac{(-x)^n}{n}$

Because the series $\sum \frac{(-x)^n}{n}$ converges to $-ln(1+x)$ when $|x|$ using the root test.

But by the properties of the natural log the series diverges at $x=-1$ because $\sum \frac{1}{n} =\infty$ and for $x=1$ we know that converges since $\sum \frac{-1}{n}$ is an alternating series that converges because the expression tends to 0.

6 0

3 years ago

6358 was rounded to the nearest one. What is the lower bound?