What is slopes and how do you solve them?

Winnie wrote the following riddle.I am a number between 60 and 100.My ones digit is two less than my tens digit.I am a prime num

Kazeer [188]

Answer:

79

Step-by-step explanation:

60<xy<100

y -2 =x

if it is prime

y cannot be even

so y could be 1,3,5,7,9

x would then be 9,1,3,5,7

but to be between 60 and 100

x must be 7 or 9

so the number must be 79 or 57

57 is not prime so

the number is 79

5 0

3 years ago

Solve for c<br> 4(3+c)+c=c+4

Sonja [21]

Answer:

c = -2

Step-by-step explanation:

Given equation is :

4(3+c)+c=c+4

12 + 4c + c = c + 4

12 + 4c = 4 [dividing by 4]

3 + c = 1 [adding and subtracting 3]

c = -2

6 0

3 years ago

Read 2 more answers

Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized

Roman55 [17]

Answer:

Option B.

Step-by-step explanation:

The given triangle is a right angle triangle.

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

In the given triangle,

$\tan (45^{\circ})=\dfrac{v}{7}$

$1=\dfrac{v}{7}$

$7=v$

Using Pythagoras theorem, we get

$hypotenuse^2=Perpendicular^2+Base^2$

$u^2=v^2+7^2$

$u^2=7^2+7^2$

$u^2=2(7^2)$

Taking square root on both sides, we get

$u=\sqrt{2(7^2)}$

$u=7\sqrt{2}$

Therefore, the correct option is B.

6 0

2 years ago

Before a bag of flour can be sold, it must be 40 kilograms but can be within 0.5

Serjik [45]

Answer:

The minimum acceptable weight of the flour bag is 39.5 kg,

and its maximum acceptable weight is 40.5 kg

Step-by-step explanation:

Notice that the selling weight of the bag to be sold (x) needs to differ from 40 kg at most 0.5 kg. Therefore, we can write the following inequality:

$|x-40|\leq 0.5$

The inequality can be solve once we remove the absolute value symbol, and solve for the unknown "x". Recall that in order to solve it, we need to consider the two possible cases:

a) that the expression within the absolute value symbol is larger than or equal to zero, and b) that the expression is less than zero.

a) If $x-40\geq 0$ then its absolute value is equal to itself (x-40), and when we remove the absolute value symbols, we get:

$x-40\leq 0.5\\x\leq 0.5+40\\x\leq 40.5\,\,kg$

which means that the weigh "x" of the flour bag should be smaller or equal than 40.5 kg

b) If $x-40$ , then the absolute value of this is its opposite : -x+40, and the inequality becomes:

$-x+40\leq 0.5\\40\leq 0.5+x\\40-0.5\leq x\\39.5\leq x$

which means that the weight of the flour bag must be larger than or equal to 39.5 kg

So, the minimum acceptable weight of the flour bag is 39.5 kg, and the maximum acceptable weight is 40.5 kg

6 0

3 years ago

Roberto must make his costume for his school play. He needs a piece of fabric that is 2 2/3 yards long and 1 1/2 yards wide. Wha

erik [133]

Answer:

He will need 8.34 yards of fabric.

Step-by-step explanation:

Given that,

The length of the fabric, l = 2 2/3 yards = 8/3 yards

The width of the fabric, b = 1 1/2 yards = 3/2 yards

We need to find the piece of fabric Roberto needs. It is equal to the perimeter of the fabric such that,

$P=2(l+b)\\\\P=2(\dfrac{8}{3}+\dfrac{3}{2})\\\\P=2\times \dfrac{25}{6}\\\\P=8.34\ \text{yards}$

So, he will need 8.34 yards of fabric.

7 0

3 years ago