What is the range for the following set of scores? Scores:6, 12, 9, 17, 11, 4, 14

Homolysis, or homolytic bond dissociation, produces a very specific type of product under certain reaction conditions. In Part 1

vekshin1

Answer:

1) R₃CO , H, H₃C, a carbon free radical

2) high temperature, ultraviolet irradiation

Explanation:

1) Homolysis leads to the formation of free radicals (species having a free electron). Thus, answer is :

R₃CO

H

H₃C

a carbon free radical

2) Homolysis require high temperature, ultraviolet irradiation.

5 0

3 years ago

Atomic weight is equal to the number of protons and neutrons in the nucleus. atomic weight is equal to the number of protons and

dlinn [17]

Atomic weight is actually calculated by the sum of protons and neutrons of that atom. It is not equal to the number. You must add them for the result

7 0

3 years ago

What is the molar mass of a gas which has a density of 0.00249 g/mL at 20.0 degrees celcius and 744.0 mm Hg?

creativ13 [48]

61.24 is the molar mass of a gas which has a density of 0.00249 g/mL at 20.0 degrees celcius and 744.0 mm Hg.

Explanation:

given that:

density = 0.00249 g/ml ( $\frac{mass}{volume}$ ) or 2.49 grams/litre

P = 744 mm Hg OR 0.978 atm

T = 20 Degrees or 293.15 Kelvin

R = 0.08206 Litre atm/mole K

molar mass =?

Formula used/

PV = nRT equation 1

here n is number of moles:

n = $\frac{mass}{atomic mass}$

putting the value of n and value of density in the equation 1:

PV = $\frac{mass}{molar mass}$ x RT

molar mass = $\frac{mass}{volume}$ x $\frac{RT}{P}$

= density x $\frac{RT}{P}$

= $\frac{2.49 x 0.08276 x 293.15}{0.978}$

= 61.24 is the molar mass of the gas.

8 0

2 years ago

Aqueous hydrochloric acid reacts with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . If of water i

Kaylis [27]

Answer:

87.9%

Explanation:

Balanced Chemical Equation:

HCl + NaOH = NaCl + H2O

We are Given:

Mass of H2O = 9.17 g

Mass of HCl = 21.1 g

Mass of NaOH = 43.6 g

First, calculate the moles of both HCl and NaOH:

Moles of HCl: 21.1 g of HCl x 1 mole of HCl/36.46 g of HCl = 0.579 moles

Moles of NaOH: 43.6 g of NaOH x 1 mole of NaOH/40.00 g of NaOH = 1.09 moles

Here you calculate the mole of H2O from the moles of both HCl and NaOH using the balanced chemical equation:

Moles of H2O from the moles of HCl: 0.579 moles of HCl x 1 mole of H2O/1 mole of HCl = 0.579 moles

Moles of H2O from the moles of NaOH: 1.09 moles of HCl x 1 mole of H2O/1 mole of NaOH = 1.09 moles

From the calculations above, we can see that the limiting reagent is HCl because it produced the lower amount of moles of H2O. Therefore, we use 0.579 moles and NOT 1.09 moles to calculate the mass of H2O:

Mass of H2O: 0.579 moles of H2O x 18.02 g of H2O/1 mole of H2O = 10.43 g

% yield of H2O = actual yield/theoretical yield x 100= 9.17 g/10.43 g x 100 = 87.9%

3 0

3 years ago

If a 2.50 liter container is filled with Ne gas at a pressure of 650 mm Hg and at 25°C, what mass of Ne is in the container?

seraphim [82]

Answer:

1.76 g is the mass of Ne is in the container.

Explanation:

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 650 mm Hg

V = Volume of the gas = 2.50 L

T = Temperature of the gas = $25^oC=[25+273]K=298K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of Ne gas = ?

Putting values in above equation, we get:

$650mmHg\times 2.50L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{650\times 2.50}{62.3637\times 298}=0.0874mol$

Also, molar mass of Ne = 20.1797 g/mol

So, $Mass = Moles\times Molar\ mass = 0.0874\times 20.1797 g = 1.76\ g$

<u>1.76 g is the mass of Ne is in the container.</u>

7 0

3 years ago