I think it’s to long to fit in a period??
1-pentyne consists of a carbon chain of 5 carbons one with a triple bond. 1-octyne is a carbon chain of 8 carbons with a triple bond at some point. It is known that the longer the carbon chain the higher the boiling point since more energy will be required to break the bonds between carbons. Based on this it is predicted that 1-octyne will have a higher boiling point than 1-pentyne.
The three of them have the same amount of electrons, so we can’t determine the right one on that ground. As you might know, Pauli said that electrons are always in the position of the lowest energy. So the first situation is impossible because there is a free place available that takes less energy. Then the 3rd situation is nor possible because if one electron has a different spin than the others, there is a magnetic obstruction that be prevented if the spin changes. This means that the second situation is the right one.
Answer:
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Explanation:
We are given a number of particles and asked to convert to moles.
<h3>1. Convert Particles to Moles </h3>
1 mole of any substance contains the same number of particles (atoms, molecules, formula units) : 6.022 *10²³ or Avogadro's Number. For this question, the particles are not specified.
So, we know that 1 mole of this substance contains 6.022 *10²³ particles. Let's set up a ratio.
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We are converting 2.98*10²³ particles to moles, so we multiply the ratio by that value.
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The units of particles cancel.
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
<h3>2. Round</h3>
The original measurement of particles (2.98*10²³) has 3 significant figures, so our answer must have the same.
For the number we found, 3 sig figs is the thousandth place.
The 8 in the ten-thousandth place (0.4948522086) tells us to round the 4 up to a 5 in the thousandth place.
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2.98*10²³ particles are equal to approximately <u>0.495 moles.</u>
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Actually Welcome to the concept of Bond Formation.
Answer is :-
B.) O and Cl
These both are Non-Metals with high Electronegativity nature, hence none of them can share electrons to foram any bond to eventually form a Electro valentines Compound.