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V125BC [204]
3 years ago
5

What fact shows that baking a chocolate chip cookie is a chemical reaction?

Chemistry
2 answers:
Setler79 [48]3 years ago
7 0

Answer:C The final product cannot be converted back to the original ingredients.

USPshnik [31]3 years ago
4 0

Answer:

its because it cant be cookie dough agian

Explanation:

c

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I what process does a solid change directly into a vapor​
Marina86 [1]

Answer:

solid change directly into a vapor in the process known simply as freezing

7 0
3 years ago
Name the reaction type & mechanism of the following reactions:
Natali5045456 [20]

Answer:

MECHANISM:

1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.

2) Formation of carbocation.

3) Attack of Nucleophile Br  −  .

Explanation:

4 0
2 years ago
Read 2 more answers
. Find the mass of 0.159 mol silicon dioxide.​
Juliette [100K]

Answer:

9.55 grams of SiO2

Explanation:

If the mass you mean by grams:

0.159 mole x 60.08 g (Periodic table by adding both elements)

Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:

9.55 grams of SiO2

4 0
2 years ago
Using words, explain all steps of dimensional analysis when converting 6.7 hectometers to meters. You must explain the set up of
sleet_krkn [62]

Answer:

  • See below

Explanation:

In order to convert 6.7 hectometers to meters using dimensional analysis, you must use the ratio of hectometers to meters.

There are 100 meters in one hectometer, then you start setting the equality: 100 m = 1 hm.

Dividing both sides by 1 hm you get the fraction form of the ratio, with meters (m) in the numerator and hectometers (hm) in the denominator.

              1m/100hm

Since hm is in the numerator, when you multiply 6.7 hm by the unit ratio the hm will be canceled and the result will have only m:

            6.7hm\times 1m/100hm=0.067m

6 0
3 years ago
How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of
alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

Explanation:

we'll apply the following equation for electric field of a point charge on a spherical conductor

E = k \frac{q}{r^{2} }

where E is the electric field

k is a constant of the value 8.99 x 10⁹ Nm²/C²

r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

E = k \frac{q}{r^{2} }

q = <u>E x r²</u>

        k

q =  <u>1250 N/C x 0.205m</u>²

       8.99 x 10⁹ Nm²/C²

q =   5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

n = \frac{q}{e}

n = <u>5.84 x 10⁻⁹ C </u>

       1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

3 0
2 years ago
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