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3 years ago

A. 0.333 B. 6 C. 0.667 D. 3

Mathematics

1 answer:

kow [346]3 years ago

8 0

Answer:

Step-by-step explanation:

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Two samples each of size 25 are taken from independent populations assumed to be normally distributed with equal variances. the

NeTakaya

$n_1=25, n_2=25\\ \bar{X_1}=35.5, \bar{X_2}=33\\ s_1=3, s_2=4$

Pooled Combined Variance $s_p=12.5$

Test Statistic:

$t=\frac{\left(\bar{X_1}-\bar{X_2}\right)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

$t=\frac{\left(35.5-33\right)}{12.5\sqrt{\frac{1}{25}+\frac{1}{25}}}$

$\left|t\right|=0.01414$

Degrees of freedom = $n_1+n_2-2=25+25-2=48$

$\alpha =0.05$

$t-Critical =t_{\alpha /2, n_1+n_2-2}=t_{0.025, 48}=-2.0206 \\Table value=|t|=2.0206\\|t|=2.0206$

The table value is greater than the calculated value.

Thus we accept H0.

8 0

3 years ago

If you add up Jasford and Jasmines ages you get 35. If Jasford is three years older than Jasmine, how old is Jasmine?

a_sh-v [17]

It is 16 I’ve done this question before

8 0

3 years ago

How many ways can a president, vice president, and secretary be selected from a class of 30 students? a. 90 b. 2,068 c. 4,060 d.

Ad libitum [116K]

Answer:

the answer to your question should be 2,068

Step-by-step explanation:

i hope i am right but i think so

7 0

2 years ago

What's the proportional relationship? I've totally forgot how to do this aaa

lubasha [3.4K]

Answer: yes it has a proportional relationship

Step-by-step explanation: Well yes it is proportional because it goes through the orgin and that is what it is if it goes through the orgin (0,0) it means it has a proportional relationship hope this helped:)

6 0

3 years ago

In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p

sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

$_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}$

We know that formula for permutations is given as

$_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}$

On substituting the given values in the formula we get,

${_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}$

$=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\
\\
=35\cdot 34\cdot 33=39270$

Therefore, there are 39270 ways in which prizes can be awarded.

6 0

3 years ago