You need to make a spring scale to measure the mass of objects hung from it. You want each 2.3 cm length along the scale to corr
2 answers:
Answer:
42.6 N/m
Explanation:
The spring constant can be found by using Hooke's law:
F = kx
where
F is the force applied
k is the spring constant
x is the stretching/compression of the spring
In this problem, the mass applied is
m = 0.10 kg
so the force applied is the weight of the mass:
The stretching of the spring is
x = 2.3 cm = 0.023 m
So the spring constant is
<u>Answer:</u> The value of spring constant is 42.6 N/m
<u>Explanation:</u>
Force is defined as the mass multiplied by the acceleration of the object.
where,
F = force exerted on the spring
m = mass = 0.10 kg
g = acceleration due to gravity =
Putting values in above equation, we get:
To calculate the spring constant, we use the equation:
where,
F = force exerted on the spring = 0.98 N
k = spring constant = ?
x = length of the spring = 2.3 cm = 0.023 m (Conversion factor: 1 m = 100 cm)
Putting values in equation 1, we get:
Hence, the value of spring constant is 42.6 N/m
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Answer:
Δy = 7.1 cm
Explanation:
The center of mass of a body is defined
= 1 /M ∑
i
Where M is the total mass of the body, m mass of each part and ‘y’ height
Let's apply this equation to our case
We locate the reference system on the shoulders
The height of the arms is at its midpoint
y = -75/2 = 37.5 cm
With arms down
= 1/70 (63 y₀ - 3.5 37.5 - 3.5 37.5)
= 1/70 (63 y)₀ - 7 37.5)
With arms up
’= 1/70 (63 y₀ + 3.5 y + 3.5 y)
’= 1/70 (63y₀ + 7 35.5)
let's subtract the two equations
’ -
= 1/70 2 (7 35.5)
Δy = ’ -
= 2 7 35.5 / 70
ΔY = 7.1 cm
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- beta plus decay: in an unstable nucleus, a proton decays into a neutron, releasing a fast moving positron and a neutrino. Following this decay, the atomic number of the nucleus decreases by 1 unit while its mass number remains the same
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