1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sindrei [870]
1 year ago
5

In places such as hospital operating rooms or factories for electronic circuit boards, electric sparks must be avoided. A person

standing on a grounded floor and touching nothing else can typically have a body capacitance of 150 pF , in parallel with a foot capacitance of 80.0 pF produced by the dielectric soles of his or her shoes. The person acquires static electric charge from interactions with his or her surroundings. The static charge flows to ground through the equivalent resistance of the two shoe soles in parallel with each other. A pair of rubber-soled street shoes can present an equivalent resistance of 5.00 ×10³ Mω. A pair of shoes with special static-dissipative soles can have an equivalent resistance of 1.00Mω . Consider the person's body and shoes as forming an R C circuit with the ground.(a) How long does it take the rubber-soled shoes to reduce a person's potential from 3.00×10³ V to 100V?
Physics
1 answer:
FrozenT [24]1 year ago
3 0

Time taken by the rubber-soled shoes to reduce a person's potential from 3.00×10³ V to 100V is 3.91s

The initial potential difference \Delta V_o is related to the final potential difference \Delta V by

\Delta V=\Delta V_{o} e^{-t / \tau}

Our target is to find t, so we rearrange equation (1) for t to be

\Delta V=\Delta V_{o} e^{-t / RC}\\ \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) = \frac{-t}{RC}\\ t= -RC \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) \tag{2}

The body has a capacitance 150 pF while the foot has a capacitance 80 pF and both are in parallel connection. So, the equivalent capacitance is

C= 150 \mathrm{~pF} + 80 \mathrm{~pF} = 230 \mathrm{~pF}

The shoes of the rubber-soled has resistance R=5000 \mathrm{~M\Omega}. Plug the values for \Delta V, \Delta V_o and C into equation (2) to get the time t.

t&= -RC \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) \\ &= -( 5000 \times 10^{6} \mathrm{~\Omega})(230 \times 10^{-12} \mathrm{~F}) \ln \left ( \frac{100\mathrm{~V}}{3000 \mathrm{~V}} \right ) \\ &= {3.91 \mathrm{~s}}

Learn more about capacitance here:

brainly.com/question/12644355

#SPJ4

You might be interested in
The Special Olympics raises money through "plane pull" events in which teams of 25 people compete to see who can pull a 74,000 k
Murrr4er [49]

Answer:

28716.4740661 N

1.2131147541 m/s

51.2474965841%

Explanation:

m = Mass of plane = 74000 kg

s = Displacement = 3.7 m

f = Frictional force = 14000 N

t = Time taken = 6.1 s

u = Initial velocity = 0

v = Final velocity

s=ut+\frac{1}{2}at^2\\\Rightarrow 3.7=0\times 6.1+\frac{1}{2}\times a\times 6.1^2\\\Rightarrow a=\frac{3.7\times 2}{6.1^2}\\\Rightarrow a=0.198871271164\ m/s^2

Force is given by

F=ma+f\\\Rightarrow F=74000\times 0.198871271164+14000\\\Rightarrow F=28716.4740661\ N

The force with which the team pulls the plane is 28716.4740661 N

v=u+at\\\Rightarrow v=0+0.198871271164\times 6.1\\\Rightarrow v=1.2131147541\ m/s

The speed of the plane is 1.2131147541 m/s

Kinetic energy is given by

K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}\times 74000\times 1.2131147541^2\\\Rightarrow K=54450.9540448\ J

Work done is given by

W=Fs\\\Rightarrow W=28716.4740661\times 3.7\\\Rightarrow W=106250.954045\ J

The fraction is given by

\dfrac{54450.9540448}{106250.954045}=0.512474965841

The teams 51.2474965841% of the work goes to kinetic energy of the plane.

3 0
3 years ago
In the picture below, the candle is heating the water in the tank. Which picture shows how the water will move as it gets hot?
Masteriza [31]

The first picture, at the top, does.

5 0
2 years ago
Read 2 more answers
Consider the f(x) = cos(x-C) function shown in the figure in blue color, where 0 ≤ C ≤ 2π. What is the value of parameter C for
klemol [59]

The value of parameter C for the function in the figure is 2.

<h3>What is amplitude of a wave?</h3>

The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.

f(x) = Acos(x - C)

where;

  • A is amplitude of the wave
  • C is phase difference of the wave

<h3>What is angular frequency of a wave?</h3>

Angular frequency is  the angular displacement of any element of the wave per unit time.

From the blue colored graph; at y = 1, x = -2 cm

1 = cos(2 - C)

(2 - C) = cos^(1)

(2 - C) = 0

C = 2

Thus, the value of parameter C for the function in the figure is 2.

Learn more about phase angle here: brainly.com/question/16222725

#SPJ1

5 0
1 year ago
Monochromatic light of wavelength 385 nm is incident on a narrow slit. On a screen 3.00 m away, the distance between the second
LiRa [457]

To solve this problem it is necessary to apply the concepts related to the concept of overlap and constructive interference.

For this purpose we have that the constructive interference in waves can be expressed under the function

a sin\theta = m\lambda

Where

a = Width of the slit

d = Distance of slit to screen

m = Number of order which represent the number of repetition of the spectrum

\theta = Angle between incident rays and scatter planes

At the same time the distance on the screen from the central point, would be

sin\theta = \frac{y}{d}

Where y = Represents the distance on the screen from the central point

PART A ) From the previous equation if we arrange to find the angle we have that

\theta = sin^{-1}(\frac{y}{d})

\theta = sin^{-1}(\frac{1.4*10^{-2}}{3})

\theta = 0.2673\°

PART B) Equation both equations we have

a sin\theta = m\lambda

a \frac{y}{d} = m\lambda

Re-arrange to find a,

a = \frac{(2)(385*10^{-9})(3)}{(1.4*10^{-2})}

a = 1.65*10^{-4}m

8 0
3 years ago
Can y'all please help me out with this ?
Inessa05 [86]

Answer:

no where is the main part of the question dude

3 0
2 years ago
Other questions:
  • I need help with this
    11·1 answer
  • If you move a negatively charged rod close to a neutral item, like a doorknob the electrons on the doorknob will
    5·2 answers
  • In most cases, letters of reconmendation are required for addmission to?
    5·1 answer
  • Allyson and Adrian have decided to connect their ankles with a bungee cord; one end is tied to each person's ankle. The cord is
    9·1 answer
  • Find the net work done by friction on the body of a snake slithering in a complete circle of 1.04 m radius. The coefficient of f
    5·1 answer
  • Students were asked to place a mint in their mouths and determine how long it took for the mint to dissolve. The condition of th
    7·2 answers
  • Where does the rest of the energy 90% go?
    6·1 answer
  • Help quick (edge 2021)
    10·1 answer
  • How can you relazie a perfect balck body in pratice​
    6·1 answer
  • 4. A net force of 15 N is exerted on a book to cause it to accelerate at a rate of 5 m/s2. Determine the mass of the
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!