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omeli [17]
3 years ago
5

Please Help! Im dumb.

Physics
2 answers:
Rus_ich [418]3 years ago
8 0
The answers false I believe
My name is Ann [436]3 years ago
3 0
The answer is false hopes this helps!
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Elements from opposite sides of the periodic table tend to form ________.
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3 years ago
Jorge visits Panama city, Florida during the month of may. he feels a shore breeze blowing from the ocean on the beach. what cau
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The answer is a.) the ocean is colder than the land.
Thus, Jorge visits Panama city, Florida during the month of may. he feels a shore breeze blowing from the ocean on the beach because Jorge visits Panama city, Florida during the month of may. he feels a shore breeze blowing from the ocean on the beach.

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3 0
3 years ago
A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the mo
Mnenie [13.5K]

Answer:

Your answer is: K.E = 8.3 J

Explanation:

If the height (h) = 169.2 meters (m) and the mass (m) is 0.005 kilograms (kg) the total energy will be kinetic energy which is equal to the potential energy.

K.E = P.E and also P.E equals to mgh

Then you substitute all the parameters into the formula  ↓

P.E = 0.005 × 9.81 × 169.2

P.E = 8.2908 J

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7 0
3 years ago
Two mass m1 and m2 lie on a frictionless surface. Between the two masses is a compressed spring, with spring constant k. The sys
max2010maxim [7]

Answer:

The spring was compressed the following amount:

\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }

Explanation:

Use conservation of energy between initial and final state, considering that the surface id frictionless, and there is no loss in thermal energy due to friction. the total initial energy is the potential energy of the compressed spring (by an amount \Delta x), and the total final energy is the addition of the kinetic energies of both masses:

E_i=\frac{1}{2} k\,(\Delta x)^2\\\\E_f=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2

E_i=E_f\\

\frac{1}{2} k\,(\Delta x)^2=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2\\k\,(\Delta x)^2=m_1\,v_1^2+ m_2\,v_2^2\\(\Delta x)^2=\frac{m_1\,v_1^2+ m_2\,v_2^2}{k} \\\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }

8 0
2 years ago
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