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3 years ago

Look at the figures. How can you prove these triangles are congruent?

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

5 0

Answer:

A. $\Delta ABC\cong \Delta DEF$ by the SAS postulate.

Step-by-step explanation:

We have been two triangles. We are asked to determine the theorem by which both triangles could be proven congruent.

We can see that side DF of triangle DEF is equal to side AC of triangle ABC.

We can also see that side BC of triangle ABC is equal to side EF of triangle DEF.

The including angle between sides AC and BC of triangle ABC is equal to the including angle between sides DF and EF of triangle DEF.

Since both triangles have two sides and their included angles equal, therefore, triangle ABC is congruent to triangle DEF by SAS (Side-Angle-Side) congruence and option A is the correct choice.

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Drako found an emerald in a cave at a depth between Negative one-half and Negative 1 and two-thirds meters. Which number could r

8090 [49]

Options :

Negative 2 and one-third meters

Negative three-fourths meters

Negative one-fourth meters

Negative 1 and

StartFraction 5 Over 6 EndFraction meters

Answer: Negative three-fourths meters

Step-by-step explanation:

Given the following :

Depth Location of Emerald :

Between - 1/2 and - 1 2/3

The answer will be the option which lies between the two depth points.

-1/2 = - 0.5 ( upper bound)

-1 2/3 = - 1.667 ( lower bound)

The option which lies inbetween :

- 1.667 and - 0.5

Taking each option :

Negative 2 and one-third meters = - 2 1/3 = - 2.33

Negative three-fourths meters = - 3/4 = - 0.75

Negative one-fourth meters = - 1/4 = - 0.25

Negative 1 and StartFraction 5 Over 6 EndFraction meters = - 1 5/6 = - 1.833

Hence, the only depth position which lies inbetween (-1.667 and - 0.5) is - 0.75

4 0

3 years ago

Read 2 more answers

Suppose a building has 5 floors (1-5) which are occupied by officesThe ground floor (0) is not

Lynna [10]

Answer: didn't know

Step-by-step explanation:

Came for points

4 0

3 years ago

How are the real solutions of a quadratic equation related to the graph of the quadratic function?

Anika [276]

The solutions you get when you solve the formula are the corresponding y coordinates to your x value. So say a point on your graph is (2,3). The first number is x and the second is y. (x,y). The number you plug into your function is x,or in this case: 2. The solution to the equation when the x value is plugged in is y, or 3. Therefore, giving you a point on your graph.

7 0

3 years ago

Needed help for my math please

vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

(a)

$\frac{a}{a}$ = 1 ( any value divided by itself = 1 )

(b)

$\frac{a}{1}$ = a ( any value divide by 1 is the value itself )

(c)

$\frac{a}{b}$ × $\frac{c}{d}$ = $\frac{ac}{bd}$

The product of 2 fractions is the product of the numerators divided by the product of the denominators

(d)

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{ad}{bc}$

To divide 2 fractions, leave the first fraction, change division to multiplication and turn the second fraction upside down, that is

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{a}{b}$ × $\frac{d}{c}$ = $\frac{ad}{bc}$

(e)

$\frac{a}{d}$ + $\frac{b}{d}$ = $\frac{a+b}{d}$

Since the fractions have a like denominator, add the numerators leaving the denominator. This applies to subtraction also

(f)

$\frac{a}{d}$ - $\frac{b}{d}$ = $\frac{a-b}{d}$

See explanation for part (e)

6 0

3 years ago

How many ways can the letters in the word balloon be arranged? 210 1,260 2,520 5,040

Lapatulllka [165]

Answer:

The number of ways this can be done is 1,260 ways

Step-by-step explanation:

In this question, we are asked to calculate the number of ways in which the letters of the word balloon can be arranged.

To do this, we take into consideration those letters that are repeated and the number of times repeated. The letters are l and o and are repeated two times each.

The number of ways = 7!/2!2! = 5040/4 = 1,260 ways

6 0

4 years ago