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Mumz [18]
3 years ago
6

Look at the figures. How can you prove these triangles are congruent?

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
5 0

Answer:

A. \Delta ABC\cong \Delta DEF by the SAS postulate.

Step-by-step explanation:

We have been two triangles. We are asked to determine the theorem by which both triangles could be proven congruent.

We can see that side DF of triangle DEF is equal to side AC of triangle ABC.

We can also see that side BC of triangle ABC is equal to side EF of triangle DEF.

The including angle between sides AC and BC of triangle ABC is equal to the including angle between sides DF and EF of triangle DEF.

Since both triangles have two sides and their included angles equal, therefore, triangle ABC is congruent to triangle DEF by SAS (Side-Angle-Side) congruence and option A is the correct choice.

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You’re so smart, I love questions like this. Hopefully you can solve it so I can know too!
8 0
3 years ago
Math help please show work thanks
GalinKa [24]

Problem 5

d = 29 = diameter

r = d/2 = 29/2 = 14.5 = radius

SA = surface area of sphere

SA = 4*pi*r^2

SA = 4*pi*(14.5)^2

SA = 841pi

SA = 841*3.14

SA = 2,640.74 square inches

To convert from square inches to square feet, we divide by 144. This is because 12^2 = 144.

2,640.74 square inches = (2,640.74)/144 = 18.3 sq ft

<h3>Answer: 18.3 square feet (approximate)</h3>

=====================================

Problem 6

d = 10.7 = diameter

r = d/2 = 10.7/2 = 5.35 = radius

L = 22.3 = slant height

SA = surface area of the cone

SA = pi*r^2 + pi*r*L

SA = pi*(5.35)^2 + pi*5.35*22.3

SA = 147.9275pi

SA = 147.9275*3.14

SA = 464.49235

<h3>Answer:  464.49235 square cm (approximate)</h3>
8 0
3 years ago
A boxer weighs 14 stone 5 lbs. To be in the heavyweight division, he must be &gt; 91 kg. What is his weight in kg to 2 decimal p
Karo-lina-s [1.5K]
14x14= 196 lb.
196/2.2= 89.09 kg.

Did that help?
4 0
2 years ago
Read 2 more answers
A sample of 20 account balances of a credit company showed an average balance of $1,170 and a standard deviation of $125. You wa
Lady_Fox [76]

Answer:

The P-value for this test is P=0.2415.

Step-by-step explanation:

We have to perform an hypothesis testing on the mean of alla account balances.

The claim is that the mean of all account balances is significantly greater than $1,150.

Then, the null and alternative hypothesis are:

H_0: \mu=1150\\\\H_a: \mu>1150

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.

We can calculate the t-statistic as:

t=\dfrac{\bar x-\mu}{s/\sqrt{n}}=\dfrac{1170-1150}{125/\sqrt{20}}=\dfrac{20}{27.95}=0.7156

The degrees of freedom fot this test are:

df=n-1=20-1=19

For this one-tailed test and 19 degrees of freedom, the P-value is:

P-value=P(t>0.7156)=0.2415

8 0
3 years ago
What is 5% of 3200? Plz help bro​
likoan [24]
5% of 3200 is 160......
7 0
2 years ago
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