<h3>Answer: Choice B. f(x) = 100 - 68x</h3>
Work Shown:
Solve for y. Then replace y with f(x).
Effectively this involves adding 1000 to both sides and subtracting 680x from both sides, afterward we divide both sides by 10 to isolate y.
Look at the figures. How can you prove these triangles are congruent?
1 answer:
Answer:
A. by the SAS postulate.
Step-by-step explanation:
We have been two triangles. We are asked to determine the theorem by which both triangles could be proven congruent.
We can see that side DF of triangle DEF is equal to side AC of triangle ABC.
We can also see that side BC of triangle ABC is equal to side EF of triangle DEF.
The including angle between sides AC and BC of triangle ABC is equal to the including angle between sides DF and EF of triangle DEF.
Since both triangles have two sides and their included angles equal, therefore, triangle ABC is congruent to triangle DEF by SAS (Side-Angle-Side) congruence and option A is the correct choice.
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We have two solutions for this problem based on the given equation.
<u><em>Answer #1:</em></u>
<u>If the given equation was:</u>
To solve for f, we would need to isolate the "f" on one side of the equation.
In case of the above equation, we can simply do that by subtracting from both sides of the equation
<u>This would give:</u>
f + -
= 6 -
f = 6 -
<u><em>Answer #2:</em></u>
<u>If the given equation was:</u>
To solve for f, we would still need to isolate the "f" on one side of the equation.
<u>This can be done as follows:</u>
................> multiply both sides by (g)
f + 4 = 6g ................> subtract 4 from both sides of the equation
f + 4 - 4 = 6g - 4
f = 6g - 4
Hope this helps :)