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Yakvenalex [24]
3 years ago
10

What is the concentration, in m/v percent, of a solution prepared from 50 g NaCl and 2.5 L of solution?

Chemistry
1 answer:
Serjik [45]3 years ago
4 0
When we convert the given mass in grams and volume in liters to m/v percent, we recall that m/v percent is expressed as grams/100 milliliters. In this case the expression becomes (50 grams/ 2500 L)*(0.1L/100ml), that is equal to 0.002 grams/ 100 mL. Hence the the concentration is equal to 0.2 m/v percent.
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Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions. If 0.212 g of KHP are dissolve
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The molarity of the NaOH solution is 0.03 M

We'll begin by calculating the mole of the KHP

  • Mass = 0.212 g
  • Molar mass = 204.22 g/mol
  • Mole of KHP =?

Mole = mass /molar mass

Mole of KHP = 0.212 / 204.22

Mole of KHP = 0.001 mole

Next, we shall determine the molarity of the KHP solution

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  • Molarity of KHP =?

Molarity = mole / Volume

Molarity of KHP = 0.001 / 0.05

Molarity of KHP = 0.02 M

Finally , we shall determine the molarity of the NaOH solution

KHP + NaOH —> NaPK + H₂O

From the balanced equation above,

  • The mole ratio of the acid, KHP (nA) = 1
  • The mole ratio of base, NaOH (nB) = 1

From the question given above, the following data were obtained:

  • Volume of acid, KHP (Va) = 50 mL
  • Molarity of acid, KHP (Ma) = 0.02 M.
  • Volume of base, NaOH (Vb) = 35 mL
  • Molarity of base, NaOH (Mb) =?

MaVa / MbVb = nA / nB

(0.02 × 50) / (Mb × 35) = 1

1 / (Mb × 35) = 1

Cross multiply

Mb × 35 = 1

Divide both side by 35

Mb = 1 / 35

Mb = 0.03 M

Thus, the molarity of the NaOH solution is 0.03 M

Complete question:

See attached photo

Learn more about titration: brainly.com/question/25866669

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Answer:

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