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ratelena [41]
3 years ago
15

Adding oil to a table would ___________ the friction when sliding a book across it.

Chemistry
2 answers:
Oksanka [162]3 years ago
5 0

Answer:

Increase

Explanation:

Hope it helps you

GrogVix [38]3 years ago
5 0

Answer:

Decrease

Explanation:

If the oil you're referring to is just some normal oil, it'll lessen the friction and cause it to side more smoothly

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Light strikes a beautiful white perch under water. This light is reflected back to your eyes allowing you to see the fish. As th
Ivahew [28]
The answer is: <span>Light strikes a beautiful white perch under water. This light is reflected back to your eyes allowing you to see the fish. As the light left the water it changes speed causing the light to bend away from the normal.
Hope this helps!
(i got this from </span>https://quizlet.com/5474123/chapter-13-light-flash-cards/ if you need more help)
7 0
3 years ago
Given the standard entropy values in the table, what is the value of º for the following reaction?
Mandarinka [93]
Hello.

The answer is <span>+313.766 J/mol·K
</span>
 Use the coefficients of the reaction and sum the product entropies less the reactant entropies:

4*188.8 + 2*213.7 - 3*205.1 - 2* 126.8 = 313.7 J/mol*K

Have a nice day
8 0
3 years ago
Why does distillation produce pure water but filtration does not?
ASHA 777 [7]

Filtration is used to separate large particles but this process does not provide pure solutions as some impurities still remain in the solution. On the other hand, distillation helps in the formation of pure water as it removes the impurities from the water or solution.

7 0
3 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

brainly.com/question/20305871

#SPJ1

5 0
2 years ago
What is empirical and moleculer formula?.
den301095 [7]
The molecular formula shows the exact number of molecules. Therefor, the empirical formula is the simplest formula of the molecular formula
4 0
3 years ago
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