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FinnZ [79.3K]
3 years ago
8

Help please! I'd appreciate it 

Chemistry
1 answer:
babymother [125]3 years ago
6 0

Answer:

16.56 g

Explanation:

Mass is the production of Volume and Density.

m = V. d = 6 × 2.76 = 16.56 g

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Explain how you can determine the number of neutrons in the nucleus of an atom of any of the elements listed in the table.
daser333 [38]

Different explanations that lead to the same result


-You need to substract the number of protons from the mass number.

-Mass number - atomic number= number of protons

-Following this  equation:

CARBON

atomic number= 6

mass number= 12

mass number= protons + neutrons

12= 6 + x

x= 12-6

x= 6



6 0
3 years ago
What is the hydronium concentration of a solution of ph 4.19M
V125BC [204]

Answer:

.000064565

Explanation:

H3O+=10^-pH

- Hope that helps! Please let me know if you need further explanation.

8 0
2 years ago
How many HCl molecules and moles are there in 3.65 grams of
ipn [44]

Answer:

0.6022×10²³ molecules

Number of moles = 0.1 mol

Explanation:

Given data:

Mass of HCl = 3.65 g

Number of molecules = ?

Number of moles = ?

Solution:

Number of moles:

Number of moles = mass/molar mass

Number of moles = 3.65 g/36.45 g/mol

Number of moles = 0.1 mol

Number of molecules:

1 mole of any substance contain 6.022×10²³ molecules

0.1 mol ×  6.022×10²³ molecules/ 1 mol

0.6022×10²³ molecules

4 0
2 years ago
True or false help please I’ll give you brainly
dimulka [17.4K]
The answer is true.
5 0
2 years ago
Read 2 more answers
A solution is prepared by dissolving 96.4 g of RbI in enough water to form 865 mL of solution. Calculate the mass % of the solut
aliya0001 [1]

Answer:

The mass % of the solution is 10.51%.

Explanation:

Mass of solute i.e. RbI = 96.4 g

Volume of the solution = 865 mL

Mass of the solution = m

Density of the solution = d = 1.06 g/mL

m=1.06 g/mL\times 865 mL=916.9 g

The mass % of the solution:

=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

=\frac{96.4 g}{916.9 g}\times 100=10.51\%

4 0
3 years ago
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