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Basile [38]
3 years ago
11

What is true about both sodium and gold?

Chemistry
2 answers:
Lina20 [59]3 years ago
6 0
Yes i agree they all are right

vladimir2022 [97]3 years ago
5 0
They all are correct , so with that being said anyone of them can be right
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Which of the following conditions would decrease the ability of a person to hear a sound? A. The distance to the sound source be
Zinaida [17]
The answer is B). A wave loses energy as it moves through a medium.
7 0
3 years ago
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Help please ASAP just with number 9
Crank
I don’t know I just need to ask a question
5 0
2 years ago
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A 2,000g of C-14 is left to decay radioactively. The half-life of Carbon-14 is approximately 5,700 years. What percentage of the
dsp73
Answer is: 12,6% (1/8) <span>percentage of the sample will remain.
</span>c₀ - initial amount of C-14.<span>
c - amount of C-14 remaining at time.
t = 5700</span> y.<span>
First calculate the radioactive decay rate constant λ:
λ = 0,693 ÷ t = 0,693 ÷ 5700</span> y = 0,000121 1/y = 1,21·10⁻⁴ y.
c = c₀·e∧-λ·t.
c = 2000 · e∧-(0,000121 1/y · 17100 y).
c = 252 g.
ω = 252 g ÷ 2000 g = 0,126 = 12,6%.
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4 0
3 years ago
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Which statements describe surface waves? Check all that apply.
neonofarm [45]

Answer:

The correct answers are "They travel slower than P waves", "They result in much ground motion" and " They are produced by P and S waves".

Explanation:

A surface wave can travel through the existing interface between Earth and air, as well as between Earth and water. A clear example of this type of waves are Love and Rayleigh waves. They travel slower than primary waves, produce large movements in the ground and are produced by primary and secondary waves.

Have a nice day!

3 0
3 years ago
If 26.4 g of hydrogen, H2, is produced from 100.0 g of methane, CH4, reacting with excess water as shown, what is the percentage
blondinia [14]

Answer: Percent yield represents the ratio between what is experimentally obtained and what is theoretically calculated, multiplied by 100%.

% yield

=

actual yield

theoretical yield

⋅

100

%

So, let's say you want to do an experiment in the lab. You want to measure how much water is produced when 12.0 g of glucose (

C

6

H

12

O

6

) is burned with enough oxygen.

C

6

H

12

O

6

+

6

O

2

→

6

C

O

2

+

6

H

2

O

Since you have a

1

:

6

mole ratio between glucose and water, you can determine how much water you would get by

12.0

g glucose

⋅

1 mole glucose

180.0 g

⋅

6 moles of water

1 mole glucose

⋅

18.0 g

1 mole water

=

7.20

g

This represents your theoretical yield. If the percent yield is 100%, the actual yield will be equal to the theoretical yield. However, after you do the experiment you discover that only 6.50 g of water were produced.

Since less than what was calculated was actually produced, it means that the reaction's percent yield must be smaller than 100%. This is confirmed by

% yield

=

6.50 g

7.20 g

⋅

100

%

=

90.3

%

You can backtrack from here and find out how much glucose reacted

65.0 g of water

⋅

1 mole

18.0 g

⋅

1 mole glucose

6 moles water

⋅

180.0 g

1 mole glucose

=

10.8

g

So not all the glucose reacted, which means that oxygen was not sufficient for the reaction - it acted as a limiting reagent.

Explanation:

6 0
2 years ago
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