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3 years ago

Which expression is equivalent to x6 – 9?

Mathematics

2 answers:

Lorico [155]3 years ago

7 0

Answer:

$(x^{3})^{2} -3^{2}$

Step-by-step explanation:

we have

$x^{6}-9$

we know that

$x^{6}-9=(x^{3})^{2} -3^{2}$

Applying difference of square

$(x^{3})^{2} -3^{2}=(x^{3}+3)(x^{3}-3)$

coldgirl [10]3 years ago

4 0

If you would like to know the equal expression to the x^6 - 9, you can do this using the following steps:

x^6 - 9 = (x^3)^2 - 3^2
(x^3)^2 = x^3 * x^3 = x^6
3^2 = 3 * 3 = 9

The correct result would be (x^3)^2 - 3^2.

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What is the greatest multiple of 7 that is less than 60

AveGali [126]

Hi there, first we find the multiples of 7, 7*1=7, 7*2=14, 7*3=21, 7*4=28, 7*5=35, 7*6=42, 7*7=49, 7*8=56, and 7*9=63. Therefore, the answer would be 56.

7 0

3 years ago

Read 2 more answers

How many people know 2 3/2 times 4,000?

PtichkaEL [24]

Answer:

14000

Step-by-step explanation:

2 x 4000= 8000 3/2 = 1 1/2, 1 x 4000= 4000, 8000+4000=12000,

1/2 x 4000 = 2000, 2000+ 12000= 14000

6 0

3 years ago

An article reported on the results of an experiment in which half of the individuals in a group of 66 postmenopausal overweight

kicyunya [14]

Answer:

We conclude that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg.

Step-by-step explanation:

We are given that an article reported on the results of an experiment in which half of the individuals in a group of 66 postmenopausal overweight women were randomly assigned to a particular vegan diet, and the other half received a diet based on National Cholesterol Education Program guidelines.

The sample mean decrease in body weight for those on the vegan diet was 6 kg, and the sample SD was 3.2, whereas, for those on the control diet, the sample mean weight loss and standard deviation were 3.8 and 2.4, respectively.

Let = true average weight loss for the vegan diet.

$\mu_2$ = true average weight loss for the control diet.

So, Null Hypothesis, : 1 kg {means that the true average weight loss for the vegan diet exceeds that for the control diet by less than or equal to 1 kg}

Alternate Hypothesis, : > 1 kg {means that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1-\barX_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_+_n_2_-_2$

where, = sample mean weight loss for the vegan diet = 6 kg

= sample mean weight loss for the control diet = 3.8 kg

= sample standard deviation weight loss for the vegan diet = 3.2 kg

= sample standard deviation weight loss for the control diet = 2.4 kg

$n_1$ = sample of vegan diet women = 33

$n_2$ = sample of control diet women = 33

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(33-1)\times 3.2^{2}+(33-1)\times 2.4^{2} }{33+33-2} }$ = 2.83

So, the test statistics = $\frac{(6-3.8)-(1)}{2.83 \times \sqrt{\frac{1}{33}+\frac{1}{33} } }$ ~ $t_6_4$

= 1.722

The value of t-test statistics is 1.722.

Also, the P-value of the test statistics is given by;

P-value = P( $t_6_4$ > 1.722) = 0.0461 or 4.61%

Since the P-value of our test statistics is less than the level of significance as 0.0461 < 0.05, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg.

3 0

3 years ago

1. SPORTS Hector wants to buy a new football. He initially thought it would cost $36, but when he went to the sporting goods sto

Talja [164]

Answer:

It cost Hector $28.8

Step-by-step explanation:

How to find the answer:

36 - 20%

= $28.8

3 0

2 years ago

felicity's quiz scores in her mathematics class were :80,94,91,80,97,99. which measure of central tendency should felicity use t

xxTIMURxx [149]

Answer:

mean

Step-by-step explanation:

5 0

3 years ago