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ycow [4]
3 years ago
11

Which equation could have the graph shown below? y = (x – 4)(x – 1)(2 + x)(3 + x) y = (x – 4)(1 – x)(2 + x)(3 + x) y = (x + 4)(x

+ 1)(2 – x)(3 – x) y = (x + 4)(x + 1)(2 – x)(x – 3)
ty
Mathematics
1 answer:
Paul [167]3 years ago
7 0
These functions are expressed in the factored form: what this means is that say for the first one y=(x-4)(x-1)(2+x)(3+x) ... when x=4, the first bracket becomes 0. Same for x=1, x=-2, x=-3 ... 

If you were to graph this, you would see that the function's line interesects the x-axis at these points... when x=4, when x=1, etc etc.

Thus, take a look at the zeroes of the graph. At which x points do they interscet the x-axis? You can determine the equation of your graph by this.
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What is an equation of the line that passes through the points (0, 3) and (5,-3)?
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Answer:

The equation of the line that passes through the points (0, 3) and (5, -3) is y = -\frac{6}{5}\cdot x +3.

Step-by-step explanation:

From Analytical Geometry we must remember that a line can be formed after knowing two distinct points on Cartesian plane. The equation of the line is described below:

y = m\cdot x + b (Eq. 1)

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

m - Slope, dimensionless.

b - y-Intercept, dimensionless.

If we know that (x_{1},y_{1}) = (0,3) and (x_{2},y_{2})=(5,-3), the following system of linear equations is constructed:

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The solution of the system is: b = 3, m = -\frac{6}{5}. Hence, we get that equation of the line that passes through the points (0, 3) and (5, -3) is y = -\frac{6}{5}\cdot x +3.

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