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3 years ago

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Write an equation of the line that passes through the point (5, –8) with slope 5. A. y−5=5(x+8) B. y+8=−5(x−5) C. y−5=−5(x+8) D.

y+8=5(x−5)

1 answer:

Ludmilka [50]3 years ago

7 0

Answer:

D

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 5 and (a, b) = (5, - 8 ), thus

y - (- 8) = 5( x - 5), that is

y + 8 = 5(x - 5) → D

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3 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

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3 years ago

Read 2 more answers

HELP ASAP with this question.

nataly862011 [7]

If y=4x+2 and x=1, we can get 4*1+2=6 for y, resulting in 1*6+1/6=2+z. Subtracting 2 from both sides, we get 4+1/6=z

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3 years ago

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OLga [1]

Answer:

5. 4 6. 6

Step-by-step explanation:

Number 5

$10-2\sqrt{9}$

$2\sqrt{9}=6$

$=10-6$

Subtract the numbers: 10 - 6 = 4

$=4$

Number 6

$70-\left(\sqrt[3]{64}\right)^3$

$\left(\sqrt[3]{64}\right)^3=64$

$=70-64$

Subtract the numbers: 70 - 64 = 6

$=6$

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3 years ago

What is the right answer

RoseWind [281]

The 3rd one is right

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3 years ago