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3 years ago

Please answer this question now

Mathematics

2 answers:

yaroslaw [1]3 years ago

7 0

Answer:

396 yd^2

Step-by-step explanation:

8X12=96

(96/2)*2=9

10*10=100

100*3=300

300+96=396

Gekata [30.6K]3 years ago

7 0

Answer:

416 yd^2

Step-by-step explanation:

The formula for the surface area of a triangular prism is

$A=2\sqrt{\frac{a+b+c}{2}(\frac{a+b+c}{2}-a)(\frac{a+b+c}{2}-b)(\frac{a+b+c}{2}-c)}+(a+b+c)h$

where h is the height (10), and a, b and c are the base sides (10, 10, 12).

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3 years ago

Choose one of the factors of x^3 + 343.

Debora [2.8K]

First, note that $343=7^3.$ Then use the formula for the sum of perfect cubes:

$a^3+b^3=(a+b)(a^2-ab+b^2).$

Therefore,

$x^3 + 343=x^3+7^3=(x+7)(x^2-7x+49).$

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Answer: correct choice is A.

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3 years ago

If it took 2 hours to clean 4 houses how many houses could be cleaned in 3 hours

leva [86]

Answer:

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

What is the radius of the cone?

gayaneshka [121]

Answer:

r = 6 in

Step-by-step explanation:

$V = \pi r^{2} \frac{h}{3}$ = $216\pi$

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r² = 216/6 = 36

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2 years ago

A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).

maksim [4K]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}$

$\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}$

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2 years ago