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IRINA_888 [86]
2 years ago
13

The diagram below shows a three dimensional view of the pool.

Mathematics
1 answer:
shutvik [7]2 years ago
5 0

Answer:

a) A_{f} = 408.54\,m^{2}, b) A_{w} = 106.2\,m^{2}

Step-by-step explanation:

a) The floor area of the pool is:

A_{f} = (10\,m)\cdot (12\,m)+(18\,m)\cdot (16.03\,m)

A_{f} = 408.54\,m^{2}

b) The total area of the walls of the pool is:

A_{w} = 2\cdot (0.9\,m)\cdot (16\,m) + (0.9\,m)\cdot (16\,m) + (18\,m)\cdot (1.8\,m)+ 2\cdot (12\,cm)\cdot (0.9\,m)+(10\,m)\cdot (0.9\,m)

A_{w} = 106.2\,m^{2}

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2 years ago
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Alexeev081 [22]

Answer:

108º

Step-by-step explanation:

to find the sum of interior angles: ( n − 2 ) × 180 = x

x = 540º

n = # of interior angles

first, solve for n

(n - 2) • 180 = 540                        distribute to 180 to (n - 2)

180n - 360 = 540                         add 360 to both sides

180n = 900                                  divide both sides by 180

n = 5

to find measure of each angle:

540 ÷ 5 = 108º

5 0
3 years ago
1 point) Use Stoke's Theorem to evaluate ∫CF⋅dr∫CF⋅dr where F(x,y,z)=xi+yj+1(x2+y2)kF(x,y,z)=xi+yj+1(x2+y2)k and CC is the bound
Drupady [299]

Answer:

0

Step-by-step explanation:

Thinking process:

\int\limits^a_b {cF} \, .dr

= \int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx curlFdS by Stoke's Theorem

= \int\limits^a_b {} \,  \int\limits^a_b {} \, < 12y, -12x, 0 > .< z_x,-z_y, 1 > dA\\= \int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< 2x, 2y, 1 > dA since z = 25-x^{2} -y^{2} \\= 0

3 0
3 years ago
All the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over. After 60 additional boxe
AveGali [126]

Answer:

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

Step-by-step explanation:

Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.

This implies that boxes are in multiples of 12

i.e. 12, or 24, or 36 or....

Let us say this as 12m for m an integer

Now additional boxes arrived =60

Total number of boxes now = 12m+60

This when arranged in stacks of 14,nothing left out

Or this is multiple of 14

12m+60 = 14n for some positive integer n.

By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.

So we say originally 24 boxes were there now 84 boxes there.

Hence both options are right.

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

3 0
2 years ago
For what value of the constant c does the above equation have x = 2 as the only solution?
Stolb23 [73]
The answer is A, -41.
Substitution:
-8(2) - (-41)
-16 + 41
25.
Square root of 25 = 5.
5 = 4x - 3.
5 = 4(2) - 3
5 = 8 - 3
5 = 5.

8 0
2 years ago
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