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Setler [38]
2 years ago
15

Write the formulas of the compounds formed by specified cations with the following anions: OH-, ClO3-, SO3^2-, HPO4^2-. . . . Ex

press your answers as chemical formulas separated by commas. Use the given order of anions.. 1)NH4+. 2)Al^3+. 3)Pb^4+
Chemistry
2 answers:
Katena32 [7]2 years ago
7 0
In the follow

<span>1)N<span>H4</span>OH,N<span>H4</span>Cl<span>O3</span>,(N<span>H4</span><span>)2</span>S<span>O3</span>,(N<span>H4</span><span>)2</span>HP<span>O4</span></span> <span>2)Al(OH<span>)3</span>,Al(Cl<span>O3</span><span>)3</span>,A<span>l2</span>(S<span>O3</span><span>)3</span>,A<span>l2</span>(HP<span>O4</span><span>)3</span></span> <span><span>3)Pb(OH<span>)4</span>,Pb(Cl<span>O3</span><span>)4</span>,Pb(S<span>O3</span><span>)2</span>,Pb(HP<span>O4</span><span>)2</span></span></span>
Lelechka [254]2 years ago
4 0

Explanation:

1)

NH_{4}^++OH^-\rightarrow NH_4OH

3NH_{4}^++ClO_3^{3-}\rightarrow (NH_4)_3ClO_{3}

2NH_{4}^++SO_3^{2-}\rightarrow (NH_4)_2SO_{3}

2NH_{4}^++HPO_{4}^{2-}\rightarrow (NH_4)_2HPO_{4}

2)

Al^{3+}+3OH^-\rightarrow Al(OH)_3

Al^{3+}+ClO_3^{3-}\rightarrow AlClO_3

2Al^{3+}+3SO_3^{2-}\rightarrow (Al)_2(SO_{3})_3

2Al^{3+}+3HPO_{4}^{2-}\rightarrow (Al)_2(HPO_{4})_3

3)

Pb^{4+}+4OH^-\rightarrow Pb(OH)_4

3Pb^{4+}+4ClO_3^{3-}\rightarrow Pb_3(ClO_3)_4

Pb^{4+}+2SO_3^{2-}\rightarrow Pb(SO_{3})_2

Pb^{4+}+2HPO_{4}^{2-}\rightarrow Pb(HPO_{4})_2

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How many liters of solution would it take to make a 0.250 M solution when you have 3.52 moles of solute?
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Answer:

The volume of solution in liters required to make a 0.250 M solution from 3.52 moles of solute is 14.08 liters of solution

Explanation:

The question relates to the definition of the concentration of a solution which is the number of moles per liter (1 liter = 1 dm³) of solution

Therefore we have;

The concentration of the intended solution = 0.250 M

Therefore, the number of moles per liter of the required resolution = 0.250 moles

Therefore, the concentration of the required solution = 0.250 moles/liter

The volume in liters of the required solution that will have 3.52 moles of the solute is given as follows;

The required volume of solution = The number of moles of the solute/(The concentration of the solution)

∴ The required volume of solution = 3.52 moles/(0.250 moles/liter) = 14.08 liters

The required volume of solution to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

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The initial temperature of the metal is 84.149 °C.

Explanation:

The heat lost by the metal will be equivalent to the heat gain by the water.  

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