Atomic mass unit is the answer
Answer:
B.
Explanation:
Elemental analysis involves the actual percentage compositions of each element in the sample of the compounds. We know that there are two different compounds here that both contain copper and oxygen. What we don't know is the actual number of copper or oxygen composed in the compounds.
An elemental composition of these compounds would thus tell us this and will give an idea of the chemical formula of each since we now know quite well the percentage composition of each of these elements
I'm not one hundred percent sure but wouldn't group selection be most harmful to the ecosystem because they cut down a group of trees all at once instead of one by one.
The chemical formula of the compound produced from the reaction of the anion (a negatively charged ion) with formula of A⁻ᵃ and a cation (a positively charged ion) with formula B⁺ˣ can be written as,
BₐAₓ
The answers to the questions above:
Row 2, Column 2: Na⁺ and NO⁻³ : Na₃NO
Row 2, Column 3: Ca²⁺ and NO⁻³ : Ca₃(NO)₂
Row 2, Column 4: Fe³⁺ and NO⁻³ : Fe₃(NO)₃
This can be furthered reduced to: FeNO
Row 2, Column 5: NH⁴⁺ and NO⁻³ : (NH)₃(NO)₄
Row 2, Column 6: Sn⁴⁺ and NO⁻³ : Sn₃(NO)₄
For the third row anion, S₂⁻
Row 3, Column 2: Na⁺ and S₂⁻ : NaS₂
Row 3, Column 3: Ca²⁺ and S₂⁻ : CaS₄
Row 3, Column 4: Fe³⁺ and Si₂⁻ : FeS₆
Row 3, Column 5: NH⁴⁺ and S₂⁻ : NHS₈
Row 3, Column 6: Sn⁴⁺ and S₂⁻ : SnS₈
For Row 4 anion, PO₃⁻⁴
Row 4, Column 2: Na⁺ and PO₃⁻⁴: <em>Na₄PO₃</em>
Row 4, Column 3: Ca²⁺ and PO₃⁻⁴ : <em>Ca₄(PO₃)₂</em>
Row 4, Column 4: Fe³⁺ and PO₃⁻⁴ : <em>Fe₄(PO₃)₃</em>
Row 4, Column 5: NH⁺⁴ and PO₃⁻⁴ : (NH)₄(PO₃)₄
This can be further simplified into <em>NHPO₃</em>
Row 4, Column 6: Sn⁴⁺ and PO₃⁻⁴ : Sn₄(PO₃)₄
This can be further simplified into <em>SnPO₃</em>
For Row 5 anion, CO₂⁻³
Row 5, Column 2: Na⁺ and CO₂⁻³ : Na₃CO₂
Row 5, Column 3: Ca²⁺ and CO₂⁻³ : Ca₃(CO₂)₂
Row 5, Column 4: Fe³⁺ and CO₂⁻³ : Fe₃(CO₂)₃
this can be further simplified into <em>FeCO₂</em>
Row 5, Column 5: NH⁴⁺ and CO₂⁻³ : (NH)₃(CO₂)₄
Row 5, Column 6: Sn⁴⁺ and CO₂⁻³ : Sn₃(CO₂)₄
Answer:
HCl contain a polar covalent bond because H is more electropositive than Cl and Cl is more electronegative than H, resulting in a dipole moment