Answer:
The partial pressure of neon in the vessel was 239 torr.
Explanation:
In all cases involving gas mixtures, the total gas pressure is related to the partial pressures, that is, the pressures of the individual gaseous components of the mixture. Put simply, the partial pressure of a gas is the pressure it exerts on a mixture of gases.
Dalton's law states that the total pressure of a mixture of gases is equal to the sum of the pressures that each gas would exert if it were alone. Then:
PT= P1 + P2 + P3 + P4…+ Pn
where n is the amount of gases present in the mixture.
In this case:
PT=PN₂ + PAr + PHe + PNe
where:
- PT= 987 torr
- PN₂= 44 torr
- PAr= 486 torr
- PHe= 218 torr
- PNe= ?
Replacing:
987 torr= 44 torr + 486 torr + 218 torr + PNe
Solving:
987 torr= 748 torr + PNe
PNe= 987 torr - 748 torr
PNe= 239 torr
<u><em>The partial pressure of neon in the vessel was 239 torr.</em></u>
Just do it and believe in you self come on man you got it
the answer is 0.0693769. 6.02x10^21 x6.94/ 6.022x10^23 is the formua you would use.
The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.
<h3>Oxidation and reduction</h3>
Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.
In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in
while that of C in CO changed from +2 to +4 in
.
Thus, NO is acting as the oxidizing agent while CO is acting is the reducing agent.
More on oxidation and reduction can be found here: brainly.com/question/13699873
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Answer:
17.136 g H2
Explanation:
First we need to convert moles of Zinc to moles of Hydrogen in order to find out how many moles of hydrogen are produced.
When we look at our balanced equation, we can see that for every mole of Zn reacting, there is 1 mol of H2 produced. (imagine a 1 in front of the elements that have no numbers in front of them)
8.5 mol Zn *
= 8.5 mol H2
Now we will convert from moles of Hydrogen to grams
The atomic mass of H2 is 2(1.008) g/1 mol... so we will use this to convert to the number of grams of Hydrogen produced..
8.5 mol H2 *
= 17.136 g H2