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Nady [450]
3 years ago
9

A lack of diversity in a population could possibly cause (2 points)

Chemistry
2 answers:
Natasha_Volkova [10]3 years ago
3 0

The answer is C, Extinction.

If there was no diversity then a single sickness could wipe out a whole population, but if the population was more varied theres a higher chance someone is more resistant to the sickness and could carry on the species life

eduard3 years ago
3 0
C is the answer I believe
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Why a common measuring system is important
Gekata [30.6K]
So scientist around the world can share there info without having to convert and doing extra work.
6 0
3 years ago
In the word equation, sodium oxide water sodium hydroxide, the formula for sodium hydroxide is represented by
d1i1m1o1n [39]
Answer:
            <span>Formula for sodium hydroxide is represented by <u>NaOH</u>.

Explanation:
                     The reaction of Sodium oxide with water is as follow,

                               Na</span>₂O  +  H₂O    →    2 NaOH
<span>
Na</span>₂O is considered as a strong basic oxide as it contains O²⁻ which has high tendency to bind with hydrogen atoms. This reaction is an exothermic reaction and is conducted in cold water to produce NaOH.<span>

</span>
4 0
3 years ago
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katrin [286]

Answer:

ALL EXCEPT

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7 0
3 years ago
The equilibrium constant, Kc, for the following reaction is 0.967 at 650 K. 2NH3(g) N2(g) 3H2(g) When a sufficiently large sampl
AlekseyPX

Answer: Concentration of NH_3 in the equilibrium mixture is 0.31 M

Explanation:

Equilibrium concentration of H_2 = 0.729 M

The given balanced equilibrium reaction is,

                 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

Initial conc.            x                0           0

At eqm. conc.     (x-2y) M     (y) M   (3y) M

The expression for equilibrium constant for this reaction will be:

3y = 0.729 M

y = 0.243 M

K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}

Now put all the given values in this expression, we get :

K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

x=0.80

concentration of NH_3 in the equilibrium mixture = 0.80-2\times 0.243=0.31

Thus concentration of NH_3 in the equilibrium mixture is 0.31 M

3 0
3 years ago
Which of the following is the correct name for the compound S3Cl2? Sulfur chloride Sulfur (III) chloride Sulfur (II) chloride Tr
Rus_ich [418]
Sulfur is not a transition metal so it does not need a Roman numeral the correct answer is Trisulfur Dichloride
8 0
3 years ago
Read 2 more answers
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