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Nady [450]
3 years ago
9

A lack of diversity in a population could possibly cause (2 points)

Chemistry
2 answers:
Natasha_Volkova [10]3 years ago
3 0

The answer is C, Extinction.

If there was no diversity then a single sickness could wipe out a whole population, but if the population was more varied theres a higher chance someone is more resistant to the sickness and could carry on the species life

eduard3 years ago
3 0
C is the answer I believe
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Molarity of 2%W/V of NaOH is
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Assume it is 1 litre and weighs 1kg.
2 percent of 1 kg is 20g.
20g divided by molar mass of NaOH.
20g divide by 40 = 0.5 mole
0.5 mole in a litre would be 0.5M
That is the answer: 0.5M
6 0
3 years ago
Which one of the atoms shown would be most likely to form a cation with a charge of 1?
olga55 [171]
Ions are stable atoms of elements formed when original atoms loose or gain electrons to form stable configuration. Anions are negatively charged ions formed when atoms gain electrons while cations are the positively charged ions formed when atoms loose electrons. In this case a charge of +1 means an atom lost one electron to form a stable configuration. Therefore, the correct answer is A
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3 years ago
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Why dilute H2SO4 is added to oxali acid solution in redox reaction​
Sphinxa [80]

To prevent the hydrolysis and to catalyse the reaction.

Explanation:

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7 0
3 years ago
_____ is the breakdown of rock by natural forces and chemical changes. A. Erosion B. Weathering C. Crystallization D. Metamorphi
sp2606 [1]

Answer:

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3 0
3 years ago
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Nh3 is a weak base (kb = 1.8 × 10–5 m) and so the salt nh4cl acts as a weak acid. what is the ph of a solution that is 0.013 m i
ankoles [38]
First, we need to get the value of Ka:

when Ka = Kw / Kb 

we have Kb = 1.8 x 10^-5 

and Kw = 3.99 x 10^-16  so, by substitution:

Ka = (3.99 x 10^-16) /  (1.8 x 10^-5) = 2.2 x 10^-11

by using the ICE table :

                 NH4+  + H2O →NH3 +  H+
intial          0.013                       0         0 

change       -X                          +X      +X

Equ        (0.013-X)                      X         X

when Ka = [NH3][H+] / [NH4+] 

by substitution:

2.2 x 10^-11 = X^2 / (0.013 - X)  by solving this equation for X

∴X = 5.35 x 10^-7

∴[H+] = X = 5.35 x 10^-7

∴PH = - ㏒[H+]
 
        = -㏒(5.35 x 10^-7)
        = 6.27
6 0
3 years ago
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