Answer:
Austin will have to buy 180 squares of carpeting.
Step-by-step explanation:
First find the dimension of the room. We do that by multiplying the width times the length and then subtracting the cut out region in the top right. And, in order to know how big that region we cut out is, we have to do a little subtraction.
We know the room is 18' long on the left side and 12' long on the right side. We subtract 12 from 18 to get 6, and we know that the cut out region is 6' long. We do the same thing with the width, 25' wide at the bottom minus 10' wide at the top and we see that the cut out is 15' wide.
18 x 25 = 450
6 x 15 = 90
450 - 90 = 360. The area of the room is 360 
Each piece of carpet is 2' by 1'. So for every 2' long, the piece of carpet is 1' wide. Each carpet piece will cover 2
. Divide 360 by 2 and you get 180.
Step-by-step explanation:
12. n^2+2n
if you insert 1 for k and then work up by inserting 2 for k and adding those together and stoping at n.
13. 8-2(2^n)
if you insert 3 for k and then work up by inserting 4 for k and adding those together and keep on going but stopping at n.
Hope that helps :)
Answer:
Vertical Asymptote:

Horizontal asymptote:
it does not exist
Step-by-step explanation:
we are given

Vertical asymptote:
we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf
we know that any log becomes -inf when value inside log is zero
so, we can set value inside log to zero
and then we can solve for x

we get

Horizontal asymptote:
we know that
horizontal asymptote is a value of y when x is +inf or -inf
For finding horizontal asymptote , we find lim x-->inf or -inf



so, it does not exist
Answer:
-2/9
Step-by-step explanation:
first you are going to distrubute 2/5, so 2/5 times x is 2/5x and 2/5 times -2 is -4/5
next you set up the problem with those two answers which gives you:
2/5x - 4/5 = 4x
then multiply both sides of the equation by 5: 2x-4=20x
next move the constant to the right side and chnage the sign: 2x=20x+4
then combine like terms: -18x=4
after that divide both sides of the equation by -18: -2/9
so x= -2/9
Answer:
<em>(J) </em>
Step-by-step explanation:
If the scale factor of dilation is greater than 1, the image is an enlargement.
If the scale factor of dilation is between 0 and 1, the image is a reduction.