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12345 [234]
3 years ago
13

HELP ASAP PLEASE!!

Chemistry
1 answer:
Debora [2.8K]3 years ago
8 0

Answer: -

1) Concentration of NaOH = 2.0 x 10⁻² M

Since NaOH is a monoacidic base,

The Hydroxide OH⁻ concentration will be the same as concentration of NaOH.

Concentration of hydroxide = [OH⁻] = 2.0 x 10⁻² M

We know the ionic product of water = 1.0 x 10⁻¹⁴

[H₃O⁺][OH⁻] = 1.0 x 10⁻¹⁴

Thus hydronium ion concentration [H₃O⁺] = \frac{1.0 x 10^-14}{2.0 x 10^ -2}

= 5.0 x 10⁻¹³ M

2) Concentration of HNO₃ = 5.0 x 10⁻⁴ M

Since HNO₃ is a monobasic acid,

[H₃O⁺] = 5.0 x 10⁻⁴ M

pH = - log [H₃O⁺] = - log [5.0 x 10⁻⁴]

= 3.3

3) Concentration of Sr(OH)₂ = 3.45 x 10⁻² M

Since Sr(OH)₂ is a diacidic base,

Concentration of OH⁻ = [OH⁻] = 2 x 3.45 x 10⁻² M

We know the ionic product of water = 1.00 x 10⁻¹⁴

[H₃O⁺][OH⁻] = 1.0 x 10⁻¹⁴

Thus hydronium ion concentration [H₃O⁺] = \frac{1.00 x 10^-14}{2 x 3.45 x 10⁻² }

= 1.45 x 10 ⁻¹³ M

pH = - log [H₃O⁺] = - log [1.45 x 10 ⁻¹³]

= 12.8

4) pH = 7.0

We know that [H₃O⁺] = 10^{-pH}

= 1.0 x 10⁻⁷ M

5) pH = 5.00

We know that [H₃O⁺] = 10^{-pH}

= 1.00 x 10⁻⁵ M

We know the ionic product of water = 1.0 x 10⁻¹⁴

[H₃O⁺][OH⁻] = 1.00 x 10⁻¹⁴

[OH⁻] = \frac{1.00x10-14}{1.00x10-5}

= 1.00 x 10⁻⁹ M

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One mole of the acid HCl requires how many moles of OH- for neutralization?
Sergeeva-Olga [200]

Answer:

One mole of the hydrochloric acid requires one mole of hydroxide ions to be neutralized.

Explanation:

Hydrochloric acid is a very strong acid an it fully dissociates at all concentrations. The neutralization of hydrochloric acid is conventional and any inorganic base such as sodium hydroxide can be used. Having a one molar hydrochloric acid solution means that for each mole of hydrochloric acid produces one mole of protons requiring one mole of hydroxide hydroxide ions to neutralize.

This can be illustrated by the equation shown below.

5 0
3 years ago
How many moles are in 8.25×10²⁵ molecules of water(H20)?​
enyata [817]

Answer:

82500000000000000000000000

Explanation:

This is the only answer I can come up with.

6 0
2 years ago
When comparing the two elements K and Ge , the more metallic element is__________ based on periodic trends alone.
Inessa [10]

Answer:

Option D and Option B

When comparing the two elements K and Ge , the more metallic element is_____K_____ based on periodic trends alone.

When comparing the two elements Sb and Pb , the more metallic element is_____Pb______ based on periodic

Explanation:

The metallic characteristic increases when we move down a column in a periodic table or when we move left in the row.

Potassium and Germanium are located on the same row, but germanium lies on the right side of potassium. Thus, potassium (K) is more metallic than Germanium (Ge)

While Lead (Pb) lies to left of Sb in the adjacent column and is also lies below Sb. Hence Pb is more metallic than Sb

7 0
3 years ago
Which option explains how purple pigments make some flower petals purple?
raketka [301]

Many of the actual chemicals in flower petals that give them their different colors are called anthocyanins. These are water-soluble compounds that belong to a bigger class of chemicals known as flavonoids. Anthocyanins are responsible for creating the colors blue, red, pink, and purple in flowers.

3 0
3 years ago
The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd
kenny6666 [7]

Answer:

The answer is "= 0.078 \ kg \ H_2".

Explanation:

calculating the moles in CH_4 =\frac{PV}{RT}

                                                =\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol

Eqution:

CH_4 +H_2O \to  3H_2+ CO \ (g)

Calculating the amount of H_2 produced:

= 12.9 \ mol CH_4 \times  \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2

So, the amount of dihydrogen produced = 0.078 \frac{kg}{s}

5 0
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