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3 years ago

Use the x-intercept method to solve the equation y=x^3-6x^2+11x-6

Mathematics

1 answer:

maxonik [38]3 years ago

3 0

Answer:

A. 1,2,3

Step-by-step explanation:

If you graph it you can see the intercepts

desmos has a great free graphing calculator

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Find the gradient of the line segment between the points (10,-4) and (6,-16).

svet-max [94.6K]

The answer is -3 . Use the gradient formula y2-y1/x2-x1

5 0

3 years ago

What is the answer to this equation? (picture attached)

SashulF [63]

Answer:

x = $\frac{42}{5}$

Step-by-step explanation:

Given

19 - $\frac{5x+6}{4}$ = 7 ( subtract 19 from both sides )

- $\frac{5x+6}{4}$ = - 12

Multiply both sides by - 4 to clear the fraction and the negative signs

5x + 6 = 48 ( subtract 6 from both sides )

5x = 42 ( divide both sides by 5 )

x = $\frac{42}{5}$

6 0

4 years ago

What is the slope of the line shown below (- 1, 8) (2, - 4)

suter [353]

Answer:

The slope of the line can be determined from the gradient equation, rise (y axis)/ run (x-axis)

Hence let (-1, 8) be A and (2, -4) be B. The slope from A to B is (-4-8)/(2-(-1))= (-12)/3= -4

Hence the gradient/ slope of the line is -4.

Step-by-step explanation:

6 0

4 years ago

Ann's Ride

Juli2301 [7.4K]

Ann went (1) for his distance

3 0

3 years ago

1. D=5.9 ft.

Shtirlitz [24]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

$\qquad \sf \dashrightarrow \:c = \pi d$

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

$\qquad \sf \dashrightarrow \:c = 2\pi r$

Now, let's move on to questions ~

<h3>First </h3>

$\qquad \sf \dashrightarrow \:3.14 \times 5.9$

$\qquad \sf \dashrightarrow \: \approx18.53 \: ft$

<h3 />

・．━━━━━━━†━━━━━━━━━．・

<h3>Second</h3><h3 /><h3 /><h3 /><h3> $\qquad \sf \dashrightarrow \:3.14 \times 3.2$ </h3>

$\qquad \sf \dashrightarrow \: \approx10.048 \: ft$

・．━━━━━━━†━━━━━━━━━．・

<h3>Third</h3>

$\qquad \sf \dashrightarrow \:3.14 \times 6.1$

$\qquad \sf \dashrightarrow \: \approx19.15 \: ft$

・．━━━━━━━†━━━━━━━━━．・

<h3>Fourth</h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 3.7$

$\qquad \sf \dashrightarrow \: \approx2×11.62 \: m$

$\qquad \sf \dashrightarrow \: \approx23.24 \: m$

・．━━━━━━━†━━━━━━━━━．・

<h3>Fifth </h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 6.2$

$\qquad \sf \dashrightarrow \: \approx2× 19.47 \: units$

$\qquad \sf \dashrightarrow \: \approx38.94 \: m$

・．━━━━━━━†━━━━━━━━━．・

<h3>Sixth</h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 5.1$

$\qquad \sf \dashrightarrow \: \approx2×16.01 \: ft$

$\qquad \sf \dashrightarrow \: \approx \: 32.02m$

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7 0

2 years ago