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elena-s [515]
3 years ago
6

To what volume should you dilute 134 mL of an 8.00 M CuCl2 solution so that 48.0 mL of the diluted solution contains 5.89 g CuCl

2? Express your answer in milliliters.
Chemistry
1 answer:
Tom [10]3 years ago
4 0

Answer:

Explanation:

Number of moles of CuCl2 initially present = volume * molar concentration

= 0.134 * 8

= 1.072 mol.

Molar mass of CuCl2 = 63.5 + (2*35.5)

= 134.5 g/mol

Mass of CuCl2 = molar mass * number of moles

= 134.5 * 1.072

= 144.184 g

Mass of CuCl2 in 48 ml = 5.89 g in 48 ml

Volume = 5.89 * (48/144.184)

= 1.96 ml.

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ahrayia [7]

Answer:

NH4Br + AgNO3 —> AgBr + NH4NO3

Explanation:

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NH4Br(aq) + AgNO3(aq) —>

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The double displacement reaction will occur as follow:

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2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
azamat

Answer:

K=1.12x10^9

Explanation:

Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

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Best regards!

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