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elena-s [515]
3 years ago
6

To what volume should you dilute 134 mL of an 8.00 M CuCl2 solution so that 48.0 mL of the diluted solution contains 5.89 g CuCl

2? Express your answer in milliliters.
Chemistry
1 answer:
Tom [10]3 years ago
4 0

Answer:

Explanation:

Number of moles of CuCl2 initially present = volume * molar concentration

= 0.134 * 8

= 1.072 mol.

Molar mass of CuCl2 = 63.5 + (2*35.5)

= 134.5 g/mol

Mass of CuCl2 = molar mass * number of moles

= 134.5 * 1.072

= 144.184 g

Mass of CuCl2 in 48 ml = 5.89 g in 48 ml

Volume = 5.89 * (48/144.184)

= 1.96 ml.

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Please describe the relationship between these pairs of compound as: isomers, identical, or unrelated
RUDIKE [14]
A.) CIS/Trans isomers
b.) constitutional isomers
c.) identical
d.) constitutional isomers
e.) identical

4 0
3 years ago
How many moles of O2 are consumed if 20 moles of SO2 are produced
tatiyna

Answer:

25

I hope this helps

5 0
3 years ago
A chemist measures the amount of hydrogen gas produced during an experiment. She finds that 264. g of hydrogen gas is produced.
Lesechka [4]

Answer:

The answer is 130.953 g of hydrogen gas.

Explanation:

Hydrogen gas is formed by two atoms of hydrogen (H), so its molecular formula is H₂. We can calculate is molecular weight as the product of the molar mass of H (1.008 g/mol):

Molecular weight H₂= molar mass of H x 2= 1.008 g/mol x 2= 2.01568 g

Finally, we obtain the number of mol of H₂ there is in the produced gas mass (264 g) by using the molecular weight as follows:

mass= 264 g x 1 mol H₂/2.01568 g= 130.9731703 g

The final mass rounded to 3 significant digits is 130.973 g

4 0
3 years ago
Calculate the amount of heat needed to boil of benzene (), beginning from a temperature of . Be sure your answer has a unit symb
Pavlova-9 [17]

Answer:

Check explanation

Explanation:

From the question, the parameters given are 64.7g of benzene,C6H6; a starting temperature of 41.9°C and bringing it to 33.2°C.

Molar mass of benzene,C6H6= 78.11236 g/mol.

Things to know: heat capacity of benzene, C6H6= 1.63 J/g.K, the heat of fusion = 9.87 kj/mol.

STEP ONE(1): ENERGY USED IN MELTING BENZENE SOLID.

Using the formula below;

Energy used in melting the solid(in JOULES) = (mass of benzene/molar mass of benzene) × heat of Fusion.

=(64.7 g of C6H6/ 78.11236(g per mol) of C6H6) × 9.87 kJ per mol.

= 8.175 J.

= 0.008175 kJ.

STEP TWO (2): ENERGY OF HEATING THE LIQUID.

It can be calculated from the formula below;

Energy= heat capacity (J/g.K) × mass of benzene× (∆T).

= 1.63 J/g.K × 64.7 × (41.9-33.2).

= 917.5J.

= 0.9175 kJ.

Energy required to boil benzene= Energy required to melt the bezene + energy required for boiling.

= 0.008175+ 0.9175.

= 0.93kJ

Approximately, 1 kJ

8 0
2 years ago
I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2CuCl2+4KI⟶2CuI+4KCl+I2. What volume
sveta [45]

Answer: 4.7432 L

Explanation:

Use stoichiometry: .4235 mol CuCl2 (1 mol I2 / 2 mol CuCl2)(22.4 L / 1 mol I2) = 4.7432 L :)

6 0
2 years ago
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