Number 1 is C number 2 is B and number 3 is also B
Answer:
sodium/potassium/rubidium/caesium/francium
Explanation:
all are group I elements, so they all have similar properties
<h3>
Answer:</h3>
1.2 × 10^-11 M
<h3>
Explanation:</h3>
<u>We are given;</u>
Concentration of Hydrogen ions [H⁺] as 0.00083 M
<u>We are required to calculate the concentration of [OH⁻]</u>
We know that;
pH = - log [H⁺]
POH = -log[OH⁻]
Also, pH + pOH = 14
With the concentration of H⁺ we can calculate the pH
pH = -log 0.00083 M
= 3.08
But; pH + pOH = 14
Therefore; pOH = 14 - pH
= 14 - 3.08
= 10.92
But, pOH = -log[OH⁻]
Therefore; [OH] = -Antilog(pOH)
Hence; [OH⁻] = Antilog -10.92
= 1.2 × 10^-11 M
Therefore, [OH⁻] is 1.2 × 10^-11 M
Answer:
They bounce off.
Explanation:
They change into S-waves. They change into R-waves.
