Answer:
6.22g of CaCl₂
Explanation:
Mass of HCL = 4.09g
Mass of CaCl₂ =
equation of reaction
2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O
From equation of reaction, 2 moles of HCl produces 1 mole of CaCl₂
2(36.5)g of HCl = 111g of CaCl₂
73g of HCl will produce 111g of CaCl₂
4.09g of HCl will produce = x
73g of HCl = 111g of CaCl₂
4.09g of HCl = x
Cross multiply and solve for x
X = (111 * 4.09) / 73
X = 6.219g of CaCl₂ = 6.22g of CaCl₂
4.09g of HCl will produce 6.22g of CaCl₂
