Answer:
Neither linear nor exponential
Step-by-step explanation:
To check for a linear relationship. Find slope.
slope= (-1 - (-2)) / ( 5 - 2) = 1/3
check other points
slope = (1 - (-1) )/ (8 - 5) = 2/3
check more
slope = (4 - 1) / (11 - 8) = 3/ 3 = 1
Nope.
try assuming an exponential:
y = c * (a^x)
-2 = c* (a^2); -2/c = a^2
-1 = c *(a ^5); -1/c = a^5
1 = c * (a^8), 1/c = a^8
(-2/c)^4 = a^8 = 1/c
16/(c^4) = 1/c
c^3 = 16, then a = root (-2/ cube-root(16) )
The change from negative to postive would not work for y = c(a^x)
so...
assume y = a^x + k
-2 = a^2 + k
-1 = a^5 + k
... I would say neither..
p = (1/r) - q
In order to find this, follow the order of operations to get the answer.
1/p+q = r ----> Multiply both sides by p+q
1 = r(p + q) -----> Divide by r
1/r = p + q -----> subtract q from both sides
(1/r) - q = p
Huh? What do you mean I don't understand
Answer:
x = 41
Step-by-step explanation:
We know these angles will be equal to each other (they are across from each other, I honestly forget the term ) so we can set up an equation
Our equation from given: 104 = 3x - 19
Adding 19 to both sides 123 = 3x
Dividing both sides by 3: 41 = x
Answer: x = 41
Answer:
It's - 17x trust me it's right
